Python 如何从生成器获取字典输出，该生成器为自定义keras图像生成器输出带有字典的数组

我有一个定制的生成器，可以输出多个值来进行预测。我试图得到与给定图像对应的值，但没有成功。以下是我的输出：

e(array([[[[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     ...,

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]]],


    [[[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     ...,

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]],

     [[0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.],
      ...,
      [0., 0., 0.],
      [0., 0., 0.],
      [0., 0., 0.]]]], dtype=float16),
 {'HourTime': array([0.3848, 0.2375], dtype=float16),
  'MinTime': array([0.633, 0.862], dtype=float16),
  'SecTime': array([0.967, 0.717], dtype=float16)})

我的输出来自这里的生成器：

input_Size = 128
x,y,xrange,yrange = [136,150,47,47]
def ImGenA(directory, files_Loc, Hour, Min, Sec, batch_size):
    while True:
        batch_paths  = imgId = np.random.choice(a = files_Loc.index, size=batch_size)
        batch_input  = []
        batch_Hr     = []    
        batch_Min    = []
        batch_Sec    = []
        for i in batch_paths:
            img1 = cv2.imread(os.path.join(directory,files_Loc[i]))
            img1 = ndimage.rotate(img1, 210)
            img1 = cv2.resize (img1, (input_Size,input_Size))

            batch_input+=[img1/255]
            batch_Hr += [Hour[i]]
            batch_Min += [Min[i]]
            batch_Sec += [Sec[i]]

            batch_x = np.array(batch_input, dtype='float16')
            batch_y1 = np.array(batch_Hr, dtype='float16')
            batch_y2 = np.array(batch_Min, dtype='float16')
            batch_y3 = np.array(batch_Sec, dtype='float16')
        yield( batch_x, {'HourTime' : batch_y1, 'MinTime': batch_y2, 'SecTime': batch_y3})


    genA = ImGenA(directory=folder, files_Loc= train['ImageLoc'], Hour = train['HrPer'], Min = train['MinPer'], Sec = train['SecPer'],batch_size=2)
    b=next(genA)
    b[0][0] #provides image at position 0, but how do I find the Y output 'HourTime' at the same position?

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我很难从发电机运行时保存的输出中提取“HourTime”。对不起，我想以前有人问过，但我不确定怎么找不到答案

这很简单，一旦你开始工作

b[1]['HourTime'][0]

从字典中为位置0提供“HourTime”。

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IE.0.3848

一旦你让它工作起来，它就很简单了

b[1]['HourTime'][0]

从字典中为位置0提供“HourTime”。 即0.3848