使用Django和python迁移模型时出错

我需要一个人帮忙。我在使用Python和Django迁移模型文件时遇到以下错误。我在解释下面的错误

     Traceback (most recent call last):
  File "manage.py", line 22, in <module>
    execute_from_command_line(sys.argv)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/__init__.py", line 363, in execute_from_command_line
    utility.execute()
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/__init__.py", line 355, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 283, in run_from_argv
    self.execute(*args, **cmd_options)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 327, in execute
    self.check()
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 359, in check
    include_deployment_checks=include_deployment_checks,
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/commands/migrate.py", line 62, in _run_checks
    issues.extend(super(Command, self)._run_checks(**kwargs))
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 346, in _run_checks
    return checks.run_checks(**kwargs)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/registry.py", line 81, in run_checks
    new_errors = check(app_configs=app_configs)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/urls.py", line 16, in check_url_config
    return check_resolver(resolver)
  File "/usr/local/lib/python2.7/dist-packages/django/core/checks/urls.py", line 26, in check_resolver
    return check_method()
  File "/usr/local/lib/python2.7/dist-packages/django/urls/resolvers.py", line 254, in check
    for pattern in self.url_patterns:
  File "/usr/local/lib/python2.7/dist-packages/django/utils/functional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "/usr/local/lib/python2.7/dist-packages/django/urls/resolvers.py", line 405, in url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
  File "/usr/local/lib/python2.7/dist-packages/django/utils/functional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "/usr/local/lib/python2.7/dist-packages/django/urls/resolvers.py", line 398, in urlconf_module
    return import_module(self.urlconf_name)
  File "/usr/lib/python2.7/importlib/__init__.py", line 37, in import_module
    __import__(name)
  File "/opt/lampp/htdocs/carClinic/carClinic/urls.py", line 7, in <module>
    url(r'^admin/', admin.site.urls),
  File "/usr/local/lib/python2.7/dist-packages/django/contrib/admin/sites.py", line 280, in urls
    return self.get_urls(), 'admin', self.name
  File "/usr/local/lib/python2.7/dist-packages/django/contrib/admin/sites.py", line 264, in get_urls
    url(r'^%s/%s/' % (model._meta.app_label, model._meta.model_name), include(model_admin.urls)),
AttributeError: 'Personal' object has no attribute 'urls'

URL.py：

在这里，我需要在管理面板中显示这两个类。请帮助我解决此问题。

这就是问题所在：

admin.site.register(Service, Personal)

上述调用的第二个参数应该是ModelAdmin子类，但您要传递的是个人模型。它自然没有URL属性

:

AdminSite.register（model_或_iterable，admin_class=None， **选项）
向给定的admin_类注册给定的模型类（或类的iterable）。admin_类默认为ModelAdmin

class ServiceAdmin(admin.ModelAdmin):
    list_fields = ['cname','date_of_service']

admin.site.register(Service, ServiceAdmin)

按照惯例，像这样的代码应该放在admin.py中，而不是放在models.py中

admin.site.register(Personal)
admin.site.register(Service)

如果您想使用自己的自定义ModelAdmin

class ServiceAdmin(admin.ModelAdmin):
    list_fields = ['cname','date_of_service']

admin.site.register(Service, ServiceAdmin)

---

请张贴完整的stacktrace。请再次检查。我更新了帖子。你在应用程序的admin.py中写了什么吗？

class ServiceAdmin(admin.ModelAdmin):
    list_fields = ['cname','date_of_service']

admin.site.register(Service, ServiceAdmin)