Python 如何计算文本文件中每个人的平均人数

嗨，我想创建一个代码，读取一个文本文件并打印文件中每个人的平均值，我在文件夹中有这个

boys.txt

ed lin,3,1,4,2
thomas block,6,3,3

所以我想打印一些像

ed lin: 2.5
thomas block: 4

---

但我不知道如何继续，我的代码出现错误

请尝试将其他文件更改为：

from Functions import read_txt

file_txt = input("input file: ")
lines read_txt(file_txt)

lines = '\n'.join(['%s: %s' % (line.split(',')[0], sum(list(map(int, line.strip().split(',')[1:]))) / len(line.strip().split(',')[1:])) for line in lines])

print(lines)

输出：

ed lin: 2.5
thomas block: 4

---

我不知道为什么不允许使用格式，但如果不使用格式，它会有点太乏味。。。同时，这里还有另一种方法

with open("boys.txt", "r") as f:
    contents = f.read()

lines = contents.strip().split("\n")

for l in lines:
    boy = l.split(",")
    length = len(boy)
    score = 0
    for i in range(1, length):
         score += int(boy[i])
    average = score / (length-1)
    print("{}: {}".format(boy[0], average))

你也可以使用

from Functions import read_txt

file_txt = input("input file: ")
with open(file_txt, 'r') as f:
  lines = f.readlines()
  for line in lines:
    name = line[0: line.index(',')]
    data = [int(num) for num in (line[line.index(',')+1:].split(','))] 
    nums = len(data)
    data = sum(data)
    print(f"{name}: {data/nums}")

---

谢谢，有没有别的办法？我不能使用像%或{，}这样的字符串格式，不能在中使用，也不能使用map（）或filter（），神学院希望我学习如何在没有它的情况下做到这一点

with open("boys.txt", "r") as f:
    contents = f.read()

lines = contents.strip().split("\n")

for l in lines:
    boy = l.split(",")
    length = len(boy)
    score = 0
    for i in range(1, length):
         score += int(boy[i])
    average = score / (length-1)
    print("{}: {}".format(boy[0], average))

from Functions import read_txt

file_txt = input("input file: ")
with open(file_txt, 'r') as f:
  lines = f.readlines()
  for line in lines:
    name = line[0: line.index(',')]
    data = [int(num) for num in (line[line.index(',')+1:].split(','))] 
    nums = len(data)
    data = sum(data)
    print(f"{name}: {data/nums}")