如何使python代码看起来更干净?
我试图实践我所学的东西,所以我有了这个想法,它涵盖了我所学的大部分内容。该代码运行良好,但我希望如果有人可以看看,让我知道我可以使它更好如何使python代码看起来更干净?,python,Python,我试图实践我所学的东西,所以我有了这个想法,它涵盖了我所学的大部分内容。该代码运行良好,但我希望如果有人可以看看,让我知道我可以使它更好 print("available operations (*, +, /, -)\n\"delete\" to delete every previous calculations\n \"exit\" to stop the program ") is_running = True op = &q
print("available operations (*, +, /, -)\n\"delete\" to delete every previous calculations\n \"exit\" to stop the program ")
is_running = True
op = ""
while is_running:
try:
num1 = float(input(">> "))
except ValueError:
print("ValueError")
continue
while is_running:
op = input(">> ")
if op == "exit":
is_running = False
break
elif op == "delete":
break
try:
num2 = float(input(">> "))
except ValueError:
print("ValueError")
continue
if op == "*":
num1 = num1 * num2
print(num1)
elif op == "+":
num1 = num1 + num2
print(num1)
elif op == "-":
num1 = num1 - num2
print(num1)
elif op == "/":
num1 = num1 / num2
print(num1)
else:
print("unavailable operator")
break
您可以做的一件事是使用字典查找替换运算符的条件,如下代码所述:
import operator
def calculate(op, num1, num2):
oper = {
'+': operator.add,
'-': operator.sub,
'*': operator.mul,
'/': operator.truediv
}
try:
return oper[op](num1, num2)
except KeyError:
return 'Invalid Operator'
num1 = 40
num2 = 50
op = '*'
print(calculate(op, num1, num2))
还有一件事,您不需要使用多个try-except语句。对于所有输入,只有一条语句就足够了。在第二个输入语句中也不需要while循环。这很可能是一个问题,但您可以用字典查找替换运算符条件。噢,谢谢,这看起来好多了。我不知道操作员模块