Python 搜索twitter并从'；挖掘社交网络'；例子

我正在阅读关于“挖掘社交网络第二版”的代码，我试图了解示例6是如何工作的！ 我正试图打印

状态的长度，并输出不同的结果，下面我将显示两个代码段和每个代码段的结果，我希望有人能向我解释为什么我得到不同的结果。。。提前谢谢

1st code snippet:
q = '#python' 

count = 100

# See https://dev.twitter.com/docs/api/1.1/get/search/tweets

search_results = twitter_api.search.tweets(q=q,count=count)

statuses = search_results['statuses']


# Iterate through 5 more batches of results by following the cursor

for _ in range(5):
    print "Length of statuses", len(statuses)
    try:
        next_results = search_results['search_metadata']['next_results']
    except KeyError, e: # No more results when next_results doesn't exist
        break

输出为：

Length of statuses 100
Length of statuses 100
Length of statuses 100
Length of statuses 100
Length of statuses 100

这正是我所期待的。但如果我将此添加到上述代码中：

q = '#python' 

count = 100

# See https://dev.twitter.com/docs/api/1.1/get/search/tweets

search_results = twitter_api.search.tweets(q=q,count=count)

statuses = search_results['statuses']


# Iterate through 5 more batches of results by following the cursor

for _ in range(5):
    print "Length of statuses", len(statuses)
    try:
        next_results = search_results['search_metadata']['next_results']
    except KeyError, e: # No more results when next_results doesn't exist
        break

    # Create a dictionary from next_results, which has the following form:
    # ?max_id=313519052523986943&q=NCAA&include_entities=1
    kwargs = dict([ kv.split('=') for kv in next_results[1:].split("&") ])

    search_results = twitter_api.search.tweets(**kwargs)
    statuses += search_results['statuses']

输出将是：

Length of statuses 100
Length of statuses 200
Length of statuses 200

我的问题是，为什么第二次它只打印三批而不是五批，因为for循环设置为循环五次？？为什么它们不是100个呢
 多亏了《挖掘社交网络》一书的作者Matthew A.Russell，他回答了我的问题
我想这就是你想要的：


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