Python 在没有空格的单词之间未检测到标点符号

当检测到标点符号时，我如何分割句子。？！并且出现在两个没有空格的单词之间

例如：

预期：

['This is an example.', 
'Not working as expected.', 
'Because there isn't a space after dot.']`

+表示一个或多个某物，*表示零个或多个

如果你需要保持平衡。您可能不想拆分，但可以这样做：

splitText = re.findall(".*?[.?!]", "This is an example. Not working as expected.Because there isn't a space after dot.")

给

['This is an example.',
 ' Not working as expected.',
 "Because there isn't a space after dot."]

您可以通过使用正则表达式来修剪它们，例如“\s**？[.？！]”或只使用.trim

注：*？是懒惰或非贪婪量词，与。*相反，后者是贪婪量词

输出：

['This is an example!', 
 ' Working as expected?', 
 'Because.']

['This is an example', 
'!', 
' Working as expected', 
'?', 
'Because', 
'.', 
'']

另一个解决方案：

import re
from pprint import pprint

split_text = re.split("([?.!])", "This is an example! Working as "
    "expected?Because.")

pprint(split_text)

输出：

['This is an example!', 
 ' Working as expected?', 
 'Because.']

['This is an example', 
'!', 
' Working as expected', 
'?', 
'Because', 
'.', 
'']

---

@Zppingto是的，我刚刚注意到，编辑了答案。如果你看一下的文档，有一条注释提到拆分对空匹配不起作用，这就是原因吗？@SebastianProske哦，这很糟糕：有其他方法的解决方案吗？@Zppingto使用findall代替拆分，在我的回答中，如果句子中有常见的缩写词，如Mr.，等，这个解决方案将不起作用。它起作用，但我丢失了标点符号，这对我来说不是一个解决方案@塞巴斯蒂安·普罗斯克已经指出了这一点。。。这不能用split来完成

import re
from pprint import pprint

split_text = re.split("([?.!])", "This is an example! Working as "
    "expected?Because.")

pprint(split_text)

['This is an example', 
'!', 
' Working as expected', 
'?', 
'Because', 
'.', 
'']