Python 熊猫-格式化数据帧行不起作用
我试图格式化数据帧的行,但没有成功 我的数据帧输出是:Python 熊猫-格式化数据帧行不起作用,python,python-3.x,pandas,formatting,Python,Python 3.x,Pandas,Formatting,我试图格式化数据帧的行,但没有成功 我的数据帧输出是: X Y 443 cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9 889.825 111 ae3faf7ed08967e93d5f5ed6e10a5b256ec8c7fa 883.275 221 601f669c760687b84ec57fe1eec213e261
X Y
443 cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9 889.825
111 ae3faf7ed08967e93d5f5ed6e10a5b256ec8c7fa 883.275
221 601f669c760687b84ec57fe1eec213e26114a262 868.345
631 80f54ce2aa2839e80cd5447cb369ec31f5e1fd47 867.545
我希望输出的格式如下:
{"X": "cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9", "Y": 889.8}
{"X": "ae3faf7ed08967e93d5f5ed6e10a5b256ec8c7fa", "Y": 883.2}
我试过:
format = '{"X": "{}", "Y": {%.1f}}'.format
my_df.apply(lambda x: format(**x), 1)
以及:
以及:
没有一个对我有用。最后一次尝试(to_string
)返回以下错误:
文件“/usr/local/lib/python3.5/dist packages/pandas/io/formats/format.py”,第1781行,在get_result中fmt_values=self._format_strings()
文件“/usr/local/lib/python3.5/dist packages/pandas/io/formats/format.py”,第1961行,格式为字符串
返回[self.values中x的self.formatter(x)]
文件“/usr/local/lib/python3.5/dist packages/pandas/io/formats/format.py”,第1961行,在
返回[self.values中x的self.formatter(x)]
键错误:“' 有什么建议/帮助吗?试试看
my_df.to_dict(orient='records')
对于我来说,使用更改的最后一个解决方案: 如果可能需要新的格式列,请使用列表理解:
df['new'] = ['"X": "{}", "Y": {:.1f}'.format(i, j) for i, j in zip(df['X'], df['Y'])]
print (df)
X Y \
443 cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9 889.825
111 ae3faf7ed08967e93d5f5ed6e10a5b256ec8c7fa 883.275
221 601f669c760687b84ec57fe1eec213e26114a262 868.345
631 80f54ce2aa2839e80cd5447cb369ec31f5e1fd47 867.545
new
443 "X": "cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9...
111 "X": "ae3faf7ed08967e93d5f5ed6e10a5b256ec8c7fa...
221 "X": "601f669c760687b84ec57fe1eec213e26114a262...
631 "X": "80f54ce2aa2839e80cd5447cb369ec31f5e1fd47...
成功了。但X值打印为“cd2a9dd781c1396d4000ae05fcc3a…”,这是不完整的。为了输出完整的字符串,我可以做什么?“cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9”而不是“cd2a9dd781c1396d4000ae05fcc3a…”?谢谢。@Dalton Cézane这是显示问题,解决方案是
my_df.to_dict(orient='records')
df = df.to_string(formatters={'X':'"X": "{}",'.format, 'Y':'"Y": {:.1f}'.format})
print (df)
X Y
443 "X": "cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9", "Y": 889.8
111 "X": "ae3faf7ed08967e93d5f5ed6e10a5b256ec8c7fa", "Y": 883.3
221 "X": "601f669c760687b84ec57fe1eec213e26114a262", "Y": 868.3
631 "X": "80f54ce2aa2839e80cd5447cb369ec31f5e1fd47", "Y": 867.5
df['new'] = ['"X": "{}", "Y": {:.1f}'.format(i, j) for i, j in zip(df['X'], df['Y'])]
print (df)
X Y \
443 cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9 889.825
111 ae3faf7ed08967e93d5f5ed6e10a5b256ec8c7fa 883.275
221 601f669c760687b84ec57fe1eec213e26114a262 868.345
631 80f54ce2aa2839e80cd5447cb369ec31f5e1fd47 867.545
new
443 "X": "cd2a9dd781c1396d4000ae05fcc3a0b00a5dc4f9...
111 "X": "ae3faf7ed08967e93d5f5ed6e10a5b256ec8c7fa...
221 "X": "601f669c760687b84ec57fe1eec213e26114a262...
631 "X": "80f54ce2aa2839e80cd5447cb369ec31f5e1fd47...