将纬度和经度放入距离矩阵中，使用python的google map API

我有一个熊猫数据框，格式如下：

现在我想把所有的起始纬度和起始经度对放到原点，把所有的结束纬度和结束经度对放到目的地。预期产出：

    Rental Id | Distance | Duration | Status
0   51649420    0          0          OK
1   51649421    959        214        OK
2  
...
15

我尝试了以下两种方法，但它们都给了我超时错误

方法1：

import googlemaps
from pandas.io.json import json_normalize
gmaps = googlemaps.Client(key='my API key')
for i in range (0,15):
origins = (journeydf['Start Latitude'][i], journeydf['Start Longitude'][i])
destinations = (journeydf['End Latitude'][i], journeydf['End Longitude'][i])
matrix = gmaps.distance_matrix(origins, destinations, mode="bicycling")
matrixdf = json_normalize(matrix,['rows','elements'])
matrixdf['Rental Id']=journeydf['Rental Id']

方法2：

import urllib, json, time
import pandas as pd

def google(lato, lono, latd, lond):

url = """http://maps.googleapis.com/maps/api/distancematrix/json?origins=%s,%s"""%(lato, lono)+  \
"""&destinations=%s,%s&mode=driving&language=en-EN&sensor=false"""% (latd, lond)

#CHANGE THIS FOR PYTHON 3.X TO urllib.request.urlopen(url)...
response = urllib.urlopen(url).read().decode('utf8')

#Wait a second so you don't overwhelm the API if doing lots of calls
time.sleep(1)

obj = json.loads(response)
try:
    minutes =   obj['rows'][0]['elements'][0]['duration']['value']/60
    miles = (obj['rows'][0]['elements'][0]['distance']['value']/100)*.62137 #kilometers per mile
    return minutes, miles
except IndexError:
    #something went wrong, the result was not found
    print (url)
    #return the error code
    return obj['Status'], obj['Status']

def ApplyGoogle(row):
lato, lono = row['Start Latitude'], row['Start Longitude']
latd, lond = row['End Latitude'], row['End Longitude']
return google(lato, lono, latd, lond)

journeydf['Minutes'], journeydf['Miles'] = zip(*journeydf.apply(ApplyGoogle, axis = 1))

---

有没有办法解决这个问题？提前感谢。

我很惊讶方法1出现超时错误。你能确认输出吗

您是否创建了谷歌地图API密钥？标准使用免费（每天2500次距离计算，每次查询限制100次，每10秒限制100次） 该密钥需要在代码具有“MyAPI密钥”的地方编写

您在for循环上的缩进以及分配给起始点和目的地也可能存在问题。试试这个：

# make sure you can connect to Google's server
import requests
try:
  response = requests.get('http://www.google.com')
except:
  print 'Can\'t connect to Google\'s server'
  raw_input('Press any key to exit.')
  quit()

# use the Google Maps API
import googlemaps
gmaps = googlemaps.Client(key='YOUR KEY')
origins = []
destinations = []
for i in range (0,15):
  origins.append(str(journeydf['Start Latitude'][i]) + ' ' + str(journeydf['Start Longitude'][i]))
  destinations.append(str(journeydf['End Latitude'][i]) + ' ' + str(journeydf['End Longitude'][i]))
matrix = gmaps.distance_matrix(origins, destinations, mode="bicycling")
print matrix

---

16*16=256>100，因此可能尝试使用更小的矩阵，即10 X 10，然后它应该可以工作。

但我仍然收到超时错误。我已经创建了谷歌地图API，并将其放入“我的API密钥”中。当我1岁的时候，它确实适用于特定的情况。我认为在循环中有一个问题。我也有过超时，这实际上帮助了我。我有144种组合，减少到96种，效果很好。