Python 斐波那契序列
我试图理解Python,但我还是不懂。我对这门语言不熟悉,想正确地理解它。 这是使用循环的斐波那契序列的一条线。请解释此代码的含义。我正试着用手拿图案。我得到了3的模式,但3之后我没有得到答案Python 斐波那契序列,python,loops,python-3.x,iterator,iterable-unpacking,Python,Loops,Python 3.x,Iterator,Iterable Unpacking,我试图理解Python,但我还是不懂。我对这门语言不熟悉,想正确地理解它。 这是使用循环的斐波那契序列的一条线。请解释此代码的含义。我正试着用手拿图案。我得到了3的模式,但3之后我没有得到答案 a, b = 0, 1 while b < 50: print(b) a, b = b, a + b a,b=0,1 b>>b
a, b = 0, 1
while b < 50:
print(b)
a, b = b, a + b
a,b=0,1
b<50时:
印刷品(b)
a、 b=b,a+b
它是多重分配(或元组解包)
根据:
斐波那契数列:
... # 两个元素之和定义下一个元素
... a、 b=0,1
>>>b<10时:
... 印刷品(b)
... a、 b=b,a+b
...
1.
1.
2.
3.
5.
8.
本例介绍了几个新特性
第一行包含一个多重赋值:变量a和b
同时获取新值0和1。最后一行是
再次使用,表明右侧的表达式
在进行任何作业之前,首先对所有作业进行评估。这个
右侧表达式从左到右求值
这称为多重分配。它基本上是原子版本的:
a = b
b = a + b
所谓原子,我的意思是,右边的所有内容都是在调整到左边的变量之前计算出来的。因此a
变成b
,b
变成a
加b
的旧版本,相当于非原子:
old_a = a
a = b
b = old_a + b
所以,就你所看到的而言:
a b output
================ ========================= ======
(initial values) (initial values)
0 1 1
(becomes prev b) (becomes sum of prev a,b)
1 1 1
1 2 2
2 3 3
3 5 5
5 8 8
具体代码(以及多个作业的解释)可以在教程中找到。多个答案如何
def fib(num):
a = 0
b = 1
while b <= num:
prev_a = a
a = b
b = prev_a +b
#print b
return a
print fib(13)
def pythonic_fib(num):
a,b = 0,1
while b <= num:
a,b = b, a+b
return a
print pythonic_fib(13)
def recursive_fib(num, a, b):
if (b >= num):
return b
else:
return recursive_fib(num, b, a+b)
print recursive_fib(13, 0, 1)
def fib(num):
a=0
b=1
虽然b我知道这是一个老问题,但我想我已经用2美分解决了,因为对于斐波那契序列(在给定的答案之外),很多问题似乎有点过于复杂,以防有人还在看。您可以这样做:
a=1
b=0
while b<400:
a=a+b
b=a+b
print(a)
print(b)
a=1
b=0
B这里没有迭代器。
def fib(num):
a = 0
b = 1
while b <= num:
prev_a = a
a = b
b = prev_a +b
#print b
return a
print fib(13)
def pythonic_fib(num):
a,b = 0,1
while b <= num:
a,b = b, a+b
return a
print pythonic_fib(13)
def recursive_fib(num, a, b):
if (b >= num):
return b
else:
return recursive_fib(num, b, a+b)
print recursive_fib(13, 0, 1)
#The easy way to generate Fibonacci series in python is
user = input('Please enter the integer range for Fibonacci series: '); # take input from user form the range of Fibonacci series.
try:# to ignore wrong inputs and be aware from error we use try and except block
d=int(user);# converts the user input to type integer.
a=0; #initialization``
b=1; #initialization
print(a,b,end=' '); # print initial value of a and b
for c in range(0,d): # here c is iterable variable and in range o is the starting point and d is the ending range which we get from user
c=a+b;
a=b;
b=c;
print(c,end=' ');
except Exception as e:
print(e); # if any error occurred in the input here it shows which error occurs
a= int(input("Enter the first number:"));
Enter the first number:0
b= int(input("enter the second number:"));
enter the second number:1
n= int (input("enter the number of terms:"));
enter the number of terms:10
print(a,b);
0 1
while(n>2):
c=a+b;
a=b;
b=c;
print(c);
n=n-1;
1
2
3
5
8
13
21
34
a=1
b=0
while b<400:
a=a+b
b=a+b
print(a)
print(b)