Python 返回顺序输出的计数函数

是否有这样一个函数，每次调用关键字或操作时，它都会触发一个返回或计数，以更改为可以分配输出的值 这意味着根据您说“喝一杯”的次数，输出将发生变化，直到（在以下情况下）其“全部为空：

如果action=“喝一杯”

行动：喝一杯

add 1 to count.drink

count 0 = print("full")

count 1 = print ("3/4 left")

count 2 = print("1/2 left")

count 3 = print ("1/4 left")

count 4 = print("all empty")

count = 1

reaction "3/4 left"

count = 2

reaction "1/2 left"

count = 3   

reaction "1/4 left"

count = 4

reaction "all empty"

行动：喝一杯

add 1 to count.drink

count 0 = print("full")

count 1 = print ("3/4 left")

count 2 = print("1/2 left")

count 3 = print ("1/4 left")

count 4 = print("all empty")

count = 1

reaction "3/4 left"

count = 2

reaction "1/2 left"

count = 3   

reaction "1/4 left"

count = 4

reaction "all empty"

行动：喝一杯

add 1 to count.drink

count 0 = print("full")

count 1 = print ("3/4 left")

count 2 = print("1/2 left")

count 3 = print ("1/4 left")

count 4 = print("all empty")

count = 1

reaction "3/4 left"

count = 2

reaction "1/2 left"

count = 3   

reaction "1/4 left"

count = 4

reaction "all empty"

行动：喝一杯

add 1 to count.drink

count 0 = print("full")

count 1 = print ("3/4 left")

count 2 = print("1/2 left")

count 3 = print ("1/4 left")

count 4 = print("all empty")

count = 1

reaction "3/4 left"

count = 2

reaction "1/2 left"

count = 3   

reaction "1/4 left"

count = 4

reaction "all empty"

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在我的评论之后，我将提出一个解决方案

actDictCount = {"take a drink":0}

actDictList = {"take a drink":["action1","action2","action3"]}

action = "take a drink"

actDictCount[action] +=1

print(actDictList[action][actDictCount[action]])

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我建议使用Dictionary来解决这个问题。python中的Dictionary可以调用函数/方法。您可以将“take a drink”设置为键，并增加dict。