Python数组组计数

在Python中，我有一个数组

("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")

我需要一个显示计数的输出

("192.168.1.1","high",2),("192.168.1.1","low",2),("192.168.1.2","high",1),("192.168.1.2","medium",1)

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如果您不关心订单，请任何人帮助我：

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

list(set([(*t, l.count(t)) for t in l]))

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如果您不关心订单：

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

list(set([(*t, l.count(t)) for t in l]))

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您可以使用集合中的计数器

from collections import Counter

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

counter = Counter(l)

result = [(*key, counter[key]) for key in counter]

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您可以使用集合中的计数器

from collections import Counter

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

counter = Counter(l)

result = [(*key, counter[key]) for key in counter]

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[*t，数组中t的借词]您能展示一下您的尝试吗？@ChristianDean它会为每个项目的出现添加每个元素，例如192.168.1.1，高，2它会出现两次。回答注意：请停止回答这个问题。像这样的问题涉及面很广，应该就此结束，而不是回答。有关更多详细信息，请参见。[*t，数组中的t的借词]您可以显示您尝试过的内容吗？@ChristianDean它将为每个项目的出现添加每个元素，例如，对于192.168.1.1，高，2，它将出现两次。回答注意：请停止回答此问题。像这样的问题涉及面很广，应该就此结束，而不是回答。有关更多详细信息，请参阅。