Python 从列表中生成图像
我试图在Python中从1和0的列表中创建一个图像Python 从列表中生成图像,python,python-imaging-library,pillow,Python,Python Imaging Library,Pillow,我试图在Python中从1和0的列表中创建一个图像 from PIL import Image img1 = Image.open('Image1.gif') #the image is strictly black and white img1_size = img1.size img1_k = [] for i in range(img1_size[0]): for j in range(img1_size[1]): tmp_pix = img1.getpix
from PIL import Image
img1 = Image.open('Image1.gif') #the image is strictly black and white
img1_size = img1.size
img1_k = []
for i in range(img1_size[0]):
for j in range(img1_size[1]):
tmp_pix = img1.getpixel((i,j))
if (tmp_pix>127):
img1_k.append(1)
else:
img1_k.append(0)
img = Image.new('RGB', (img1_size[1],img1_size[0]), "white")
cmap = {1: (255,255,255),
0: (0,0,0)}
data = [cmap[i] for i in img1_k]
img.putdata(data)
img.show()
img.save('Image2.png')
但是,不是原始图像:
该代码生成旋转和反转图像:
我猜putdata()的格式与我获取列表像素的方式不同。如何才能获得正确的图片?getpixel,
putpixel
基于x-y坐标,而getdata
,putdata
基于行-列坐标
首先,您需要使img_k
行-列为基础:
for j in range(img1_size[1]): # row (y)
for i in range(img1_size[0]): # column (x)
tmp_pix = img1.getpixel((i,j))
if tmp_pix > 127:
img1_k.append(1)
else:
img1_k.append(0)
其次,您需要创建x*y大小的图像:
img = Image.new('RGB', (img1_size[0], img1_size[1]), "white") # <--
# OR Image.new('RGB', img1.size, "white")
cmap = {1: (255,255,255),
0: (0,0,0)}
data = [cmap[i] for i in img1_k]
img.putdata(data)
img.show()
img.save('Image2.png')
@CaiphasKain,不客气。快乐的Python编程。
from PIL import Image
img1 = Image.open('Image1.gif')
data = [(255, 255, 255) if pixel > 127 else (0, 0, 0) for pixel in img1.getdata()]
img = Image.new('RGB', img1.size, "white")
img.putdata(data)
img.show()
img.save('Image2.png')