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Python 从列表中生成图像_Python_Python Imaging Library_Pillow - Fatal编程技术网

Python 从列表中生成图像

Python 从列表中生成图像,python,python-imaging-library,pillow,Python,Python Imaging Library,Pillow,我试图在Python中从1和0的列表中创建一个图像 from PIL import Image img1 = Image.open('Image1.gif') #the image is strictly black and white img1_size = img1.size img1_k = [] for i in range(img1_size[0]): for j in range(img1_size[1]): tmp_pix = img1.getpix

我试图在Python中从1和0的列表中创建一个图像

from PIL import Image

img1 = Image.open('Image1.gif') #the image is strictly black and white
img1_size = img1.size 
img1_k = []
for i in range(img1_size[0]): 
    for j in range(img1_size[1]): 
        tmp_pix = img1.getpixel((i,j))
        if (tmp_pix>127): 
            img1_k.append(1)
        else:
            img1_k.append(0)


img = Image.new('RGB', (img1_size[1],img1_size[0]), "white") 
cmap = {1: (255,255,255),
        0: (0,0,0)}
data = [cmap[i] for i in img1_k]
img.putdata(data)
img.show()             
img.save('Image2.png')
但是,不是原始图像:

该代码生成旋转和反转图像:


我猜putdata()的格式与我获取列表像素的方式不同。如何才能获得正确的图片?

getpixel,
putpixel
基于x-y坐标,而
getdata
putdata
基于行-列坐标

首先,您需要使
img_k
行-列为基础:

for j in range(img1_size[1]):     # row (y)
    for i in range(img1_size[0]): # column (x)
        tmp_pix = img1.getpixel((i,j))
        if tmp_pix > 127:
            img1_k.append(1)
        else:
            img1_k.append(0)
其次,您需要创建x*y大小的图像:

img = Image.new('RGB', (img1_size[0], img1_size[1]), "white")  # <--
# OR  Image.new('RGB', img1.size, "white") 
cmap = {1: (255,255,255),
        0: (0,0,0)}
data = [cmap[i] for i in img1_k]
img.putdata(data)
img.show()             
img.save('Image2.png')

@CaiphasKain,不客气。快乐的Python编程。
from PIL import Image

img1 = Image.open('Image1.gif')
data = [(255, 255, 255) if pixel > 127 else (0, 0, 0) for pixel in img1.getdata()]
img = Image.new('RGB', img1.size, "white") 
img.putdata(data)
img.show()             
img.save('Image2.png')