Python 正则表达式don'；行不通

嗨，我和regex有点问题

这是一些来源：

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                            Wyniki z Google
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                    <div class="link"> <a href="http://www.google.com/glass/start/"><b>Google Glass</b></a> </div>
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                        http://www.google.com/glass/start/

                            - <a rel="nofollow" href="query.html?hl=pl&amp;qt=related:http%3A%2F%2Fwww.google.com%2Fglass%2Fstart%2F">Podobne strony</a>
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                                            <div class="desc">Thanks for exploring with us. The journey doesn&#39;t end here. You&#39;ll start to see <br />
future versions of <b>Glass</b> when they&#39;re ready (for now, no peeking).</div>
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                    <div class="link"> <a href="http://pl.wikipedia.org/wiki/Google_Glass"><b>Google Glass</b> – Wikipedia, wolna encyklopedia</a> </div>
                    <div class="source">
                        http://pl.wikipedia.org/wiki/Google_Glass

                            - <a rel="nofollow" href="query.html?hl=pl&amp;qt=related:http%3A%2F%2Fpl.wikipedia.org%2Fwiki%2FGoogle_Glass">Podobne strony</a>
                                            </div><!-- source END -->
                                            <div class="desc"><b>Google Glass</b> to okulary o rozszerzonej rzeczywistości stworzone przez firmę <br />
Google. Okulary te mają docelowo mieć funkcje standardowego smartfona, ale&nbsp;...</div>
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这是我写的<代码>'既然您是用Python编写的，我可以建议一个基于Python的解决方案

from bs4 import BeautifulSoup
html = 'YOUR STRING'
soup = BeautifulSoup(html)
divs = soup.find_all("div", {"class":"link"})

for tag in divs:
    a = tag.find_all("a")
    for t in a:
        if t.has_attr('href'):
            print t['href']

根据您的示例输入，此输出：

http://www.google.com/glass/start/
http://pl.wikipedia.org/wiki/Google_Glass

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这似乎对我有用。您能否详细说明使用正则表达式的上下文？为什么不使用X/HTML解析器？@Filburt“cannot”->“should not”您可以使用正则表达式解析有效HTML的子集，但使用解析器要比尝试确定要解析的HTML是否在该子集中好得多。

http://www.google.com/glass/start/
http://pl.wikipedia.org/wiki/Google_Glass