为什么python文件处理无法识别文件名？

我想用文件中的另一个字符串替换一个字符串。我有以下程序来执行任务

import os
import sys
import traceback
from glob import iglob


def usage():
    print('Usage: python FindAndReplace.py [Old String] [New String] '
          '[File Filters(default:".txt,.xml")] [Directory To Check(.)]')


def search_replace_string(fileName, old_str, new_str):
    if not(os.path.isfile(fileName) and os.access(fileName, os.W_OK)):
        print("Warning: Skipping..File does not exist or and is not writeable:" + filename)
        return False

    fileupdated = False

    # Read the old file

    with open(fileName, 'r') as f:
        newlines = []
        for lines in f.readlines():
            if old_str in lines:
                fileupdated = True
            line = lines.replace(old_str, new_str)
            newlines.append(line)

    # Write changes to same file

    if fileupdated:
        print("string Found and Updating File: " + fileName)
        try:
            with open(fileName, 'w') as f:
                for line in newlines:
                    f.write(line)
        except:
            print("Error: Cannot open/access existing file for writing: " + fileName)
    return fileupdated


def main():
    try:
        DEFAULT_PATH = iglob(str('<path_to_file.xml'))
        if len(sys.argv) < 3:
            usage()
            # old/new string required parameters, exit if not supplied
            sys.exit(-1)
        else:
            oldString = sys.argv[1]
            newString = sys.argv[2]

        if len(sys.argv) < 4:
            patterns = ['.xml', '.txt']

        else:
            stringFilter = sys.argv[3]
            patterns = stringFilter.split(',')

        if len(sys.argv) < 5:
            path = DEFAULT_PATH
        else:
            path = sys.argv[4]

        print('[Old String]    :' + oldString)
        print('[New String]    :' + newString)
        print('[File Filters]    :' + ', '.join(patterns))
        print('[Directory To Check]    :' + path)

        if not os.path.exists(path):
            raise Exception("Selected path does not exist: " + path)


        # Walk through directory structure looking for files matching patterns

        matchingFileList = [os.path.join(dp, f) for dp, dn, filenames in os.walk(path) for f in filenames if os.path.splitext(f)[1] in patterns]

        print('Files found matching patterns: ' + str(len(matchingFileList)))
        filecount = 0
        filesReplaced = 0

        for currFile in matchingFileList:
            filecount += 1
            filesReplaced = search_replace_string(currFile, old_str, new_str)
            if filesReplaced:
                filesReplaced += 1

        print("Total Files Searched   :" + str(filecount))
        print("Total Files Replaced/Updated  :" + str(filesReplaced))
    except Exception as err:
        print(traceback.format_exception_only(type(err), err)[0].rstrip())
        sys.exit(-1)


if __name__ == '__main__':
    main()

下面是我给出的命令行参数

python uro.py <file_path> <old_str> <new_str>

python uro.py

注意：我使用的是xml文件。 我想开发一种逻辑，将文件名、新旧字符串作为命令行参数。在错误中，可以看到程序将python文件视为输入文件。而它应该采用我用CMD参数给出的文件路径

---

这里怎么了？请建议。谢谢

我修好了，有一些路径问题。谢谢。

什么是

uro.py

与问题的其余部分有什么关系？urp.py包含搜索匹配的sting并替换为新sting的代码。哦，你的意思是

uro.py

包含你发布的代码？那么，它在哪里？代码是你自己在某种编辑器中编写的吗？你把文件保存在哪里了？我已经用pycharm写了代码。但通过CMD行执行它，参数如我的原始帖子所示。那么PyCharm在哪里存储了这个文件？在运行命令行之前，您是否已将

cd

放入此文件夹？

python uro.py <file_path> <old_str> <new_str>