Python 错误的networkx图形和可视化是丑陋的
我有一个dataframe,它由60多个(2x2)大小的值组成,下面是一些数据的示例Python 错误的networkx图形和可视化是丑陋的,python,networkx,graph-theory,Python,Networkx,Graph Theory,我有一个dataframe,它由60多个(2x2)大小的值组成,下面是一些数据的示例 label data_pairs -1040 [(-1037.13, -1044.77)] -1092 [(-1102.64, -1081.64)] -1105 [(-1107.36, -1102.64)] -137 [(-136.19, -138.75)] -1431 [(
label data_pairs
-1040 [(-1037.13, -1044.77)]
-1092 [(-1102.64, -1081.64)]
-1105 [(-1107.36, -1102.64)]
-137 [(-136.19, -138.75)]
-1431 [(-1434.08, -1429.31)]
-612 [(-622.47, -601.98)]
-672 [(-669.77, -674.95)]
-752 [(-748.22, -755.9)]
-791 [(-795.19, -788.02)]
df=pd.read_excel (r'C:\Users\xxx\Documents\Python Scripts\Python
Scripts\uuu\data_pairs.xlsx') # type: datFrame (10,2)
import networkx as nx
G = nx.DiGraph()
edges = np.stack(df.Pairs.to_numpy()).reshape(-1,2) # array of str1248 (5,2)
G = nx.from_edgelist(edges)
pos = nx.spring_layout(G, k=0.6) # dict
fig=plt.figure(figsize=(10,2),dpi=300)
nx.draw(G, pos=pos, node_size=800, with_labels=True,node_color='y')
正如数据集中的名称所示,我想为对的值绘制networkx
图,并相应地标记它们。根据StackOverflow用户的一个建议,我根据他的指导进一步修改了代码,如下所示
label data_pairs
-1040 [(-1037.13, -1044.77)]
-1092 [(-1102.64, -1081.64)]
-1105 [(-1107.36, -1102.64)]
-137 [(-136.19, -138.75)]
-1431 [(-1434.08, -1429.31)]
-612 [(-622.47, -601.98)]
-672 [(-669.77, -674.95)]
-752 [(-748.22, -755.9)]
-791 [(-795.19, -788.02)]
df=pd.read_excel (r'C:\Users\xxx\Documents\Python Scripts\Python
Scripts\uuu\data_pairs.xlsx') # type: datFrame (10,2)
import networkx as nx
G = nx.DiGraph()
edges = np.stack(df.Pairs.to_numpy()).reshape(-1,2) # array of str1248 (5,2)
G = nx.from_edgelist(edges)
pos = nx.spring_layout(G, k=0.6) # dict
fig=plt.figure(figsize=(10,2),dpi=300)
nx.draw(G, pos=pos, node_size=800, with_labels=True,node_color='y')
networkx
代码如下
label data_pairs
-1040 [(-1037.13, -1044.77)]
-1092 [(-1102.64, -1081.64)]
-1105 [(-1107.36, -1102.64)]
-137 [(-136.19, -138.75)]
-1431 [(-1434.08, -1429.31)]
-612 [(-622.47, -601.98)]
-672 [(-669.77, -674.95)]
-752 [(-748.22, -755.9)]
-791 [(-795.19, -788.02)]
df=pd.read_excel (r'C:\Users\xxx\Documents\Python Scripts\Python
Scripts\uuu\data_pairs.xlsx') # type: datFrame (10,2)
import networkx as nx
G = nx.DiGraph()
edges = np.stack(df.Pairs.to_numpy()).reshape(-1,2) # array of str1248 (5,2)
G = nx.from_edgelist(edges)
pos = nx.spring_layout(G, k=0.6) # dict
fig=plt.figure(figsize=(10,2),dpi=300)
nx.draw(G, pos=pos, node_size=800, with_labels=True,node_color='y')
边
值如下所示
[(-1037.13, -1044.77)] [(-1102.64, -1081.64)]
[(-1107.36, -1102.64)] [(-1187.16, -1192.42)]
[(-1261.33, -1280.02)] [(-136.19, -131.06)]
[(-131.06, -138.75)] [(-136.19, -138.75)]
[(-1434.08, -1429.31)] [(-304.94, -308.8), (-304.94, -307.85)]
这个networkx
graph我得到了这样的东西
正如您所看到的,这些图看起来是错误的,因为它们使用了两个值来连接图形的边
值。此外,图中未显示标签。例如,对于数据对
值[(-1037.13,-1044.77)],我应该在行之间获得标签
值-1040。类似于这样的东西(-1037.13)------------------------->(-1044.77)
和类似的东西。
-1040
以上一点只是为了理解
你能帮我怎么得到这样的结果吗?提前多谢了问题是您的列包含嵌套在列表中的元组。您需要正确构造这些值,以便networkX
按预期构建rgaph。一种简单的方法是将值堆叠到一个数组中,并适当地重塑形状
另外,nx.spring\u layout
有一个参数k
,用于设置图形中节点之间的间距:
from ast import literal_eval
from itertools import chain
df['data_pairs']= df['data_pairs'].map(literal_eval)
G = nx.from_edgelist(chain.from_iterable(df.data_pairs))
plt.figure(figsize=(10,5))
pos = nx.spring_layout(G, k=.6)
nx.draw(G,
pos=pos,
node_size=800,
with_labels=True,
node_color='y')
输入数据-
G.edges()
EdgeView([(-1037.13, -1044.77), (-1102.64, -1081.64), (-1102.64, -1107.36),
(-136.19, -138.75), (-1434.08, -1429.31), (-622.47, -601.98),
(-669.77, -674.95), (-748.22, -755.9), (-795.19, -788.02),
(-304.94, -308.8), (-304.94, -307.85)])
使用这一行并尝试定义边后,出现错误“所有输入数组必须具有相同的形状”。边缘线代码正确吗?请不要使用标签,除非您的问题涉及IGRAPHE库。非常感谢。最后一个问题,如何在节点之间显示“键”?最后:)不用担心。你说钥匙是什么意思@拉维面临着可视化问题,我把它作为一个新问题发布。你能帮我看看吗?