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Python 在管理中将整数选择值显示为字符(非整数)_Python_Django_Django Admin - Fatal编程技术网

Python 在管理中将整数选择值显示为字符(非整数)

Python 在管理中将整数选择值显示为字符(非整数),python,django,django-admin,Python,Django,Django Admin,我试图显示选项字段中的值。使用以下方法,导致“存储”模型中断(从管理员处单击) 错误是: TypeError __str__ returned non-string (type int) 当我将str更改为int时,错误停止-但它不显示区域选择(仅显示“区域对象”) 如何让它正确地返回区域作为选择(从单词列表中,而不是整数本身)?问题是您的\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

我试图显示选项字段中的值。使用以下方法,导致“存储”模型中断(从管理员处单击)

错误是:

TypeError __str__ returned non-string (type int)
当我将str更改为int时,错误停止-但它不显示区域选择(仅显示“区域对象”)


如何让它正确地返回区域作为选择(从单词列表中,而不是整数本身)?

问题是您的
\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

由于索引是存储在
self.region
中的内容,因此您只需进行查找:

class Region(models.Model):
    ...
    def __str__(self):
        return Region_CHOICES[self.region][1]

只需键入cast to string

def __str__(self):
    return str(self.region)

这对我很有用

这也给了我一个TypeError-str返回的非字符串(type tuple)。这是完整的回溯啊,很抱歉。更新了响应。
返回self.get\u region\u display()
也将起作用。看见
def __str__(self):
    return str(self.region)