Python 如何制作两种不同的方法

我建立了一个矩阵计算器和

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我想用一个mul方法进行标量乘法，另一个方法进行其他矩阵乘法。我有一个if-else块，但我更喜欢用两种不同的方法，但我希望它们都使用*操作符。我应该怎么做呢？

您可以使用

\uuuuMul\uUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUuUu

导入工具
类别矩阵：
@functools.singledispatchmethod
定义多个（自身、其他）：
引发未实施错误（其他）
@__多重寄存器
定义（自身，其他：int）：
打印（'int'）
@__多重寄存器
定义（自身、其他：str）：
打印（'str'）

Matrix（）*1#'int'
矩阵（）*'a'#'str'
functools.singledispatchmethod
似乎适合您所描述的内容。另一个示例使用参数注释指定类型，也可以将它们指定为装饰器的参数：

>>> class Foo:
...     def __init__(self, value):
...         self._value = value
... 
...     @functools.singledispatchmethod
...     def __mul__(self, other):
...         print("hmm...")
... 
...     @__mul__.register(int)
...     def _(self, other):
...         print("Using the int version.")
...         return self._value * other
... 
...     @__mul__.register(list)
...     def _(self, other):
...         print("Using the list version.")
...         return [item * self._value for item in other]
...         
>>> f = Foo(8)
>>> f * 3
Using the int version.
24
>>> f * [1, 2, 3]
Using the list version.
[8, 16, 24]

如果使用早于3.8的Python版本（在本例中，最好只在单个方法中执行类型检查，而不使用decorator）：

使用
\uuuuuuuuuuuu
（
*
）和
\uuuuuuuuuuuuuu
（
@
）。
功能工具。我想到了singledispatch
。大家好，欢迎来到StackOverflow！您在这里询问的是
\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
，但这篇关于
\uuuuuuuuuuuuuuuuuuuuuu。尽管遗憾的是，那里的解决方案似乎无法帮助您定义两种不同的方法。
>>> class Foo:
...     def __init__(self, value):
...         self._value = value
...         self.mul = functools.singledispatch(self.mul)
...         self.mul.register(int, self.mul_int)
...         self.mul.register(list, self.mul_list)
... 
...     def __mul__(self, other):
...         return self.mul(other)
... 
...     def mul(self, other):
...         print("Default mul() called.")
... 
...     def mul_int(self, other):
...         print("Using the int version.")
...         return self._value * other
... 
...     def mul_list(self, other):
...         print("Using the list version.")
...         return [item * self._value for item in other]
...         
>>> f = Foo(3)
>>> f * 7
Using the int version.
21
>>> f * [1, 2, 3]
Using the list version.
[3, 6, 9]
>>>