如何从列表在python中创建多维数组？

我有一个包含如下元素的列表

list1 = [['Test Name', 'Results', 'Units', 'Bio. Ref. Interval'], 
         ['Cholesterol, Total', '243.00', 'mg/dL', '<200.00'], 
         ['Triglycerides', '365.00', 'mg/dL', '<150.00'], 
         ['HDL Cholesterol', '48.56', 'mg/dL', '>50.00'], 
         ['LDL Cholesterol, Calculated', '121.44', 'mg/dL', '<100.00'], 
         ['VLDL Cholesterol, Calculated *', '73.00', 'mg/dL', '<30.00'], 
         ['Non-HDL Cholesterol', '194', 'mg/dL', '<130']]

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我是python的新手。请提供帮助。

您需要字典的唯一键，以便执行以下操作：

dict1 = {f'Test {j}': {list1[0][i]: list1[j][i] for i in range(4)} for j in range(1, len(list1))}

将具有以下输出

{'Test 1': {'Test Name': 'Cholesterol, Total', 'Results': '243.00', 'Units': 'mg/dL', 'Bio. Ref. Interval': '<200.00'},
 'Test 2': {'Test Name': 'Triglycerides', 'Results': '365.00', 'Units': 'mg/dL', 'Bio. Ref. Interval': '<150.00'},
 'Test 3': {'Test Name': 'HDL Cholesterol', 'Results': '48.56', 'Units': 'mg/dL', 'Bio. Ref. Interval': '>50.00'},
 'Test 4': {'Test Name': 'LDL Cholesterol, Calculated', 'Results': '121.44', 'Units': 'mg/dL', 'Bio. Ref. Interval': '<100.00'},
 'Test 5': {'Test Name': 'VLDL Cholesterol, Calculated *', 'Results': '73.00', 'Units': 'mg/dL', 'Bio. Ref. Interval': '<30.00'},
 'Test 6': {'Test Name': 'Non-HDL Cholesterol', 'Results': '194', 'Units': 'mg/dL', 'Bio. Ref. Interval': '<130'}}

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将列表转换成词典有几种方法，一种是dict理解法，另一种是zip方法

参考此->

输出将是字典列表。不是字典的字典，因为我们这里需要钥匙

您需要知道如何迭代列表和列表上的切片操作。 您应该知道zip函数是如何工作的。 以及列表的附加方法。 代码：

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请求的输出不能是字典，因为没有提到键，而只是字典列表

my_list_of_dictionaries = [{k:i[list1[0].index(k)] for k in list1[0]} for i in list1[1:]]

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是否希望密钥包含在一个完整的字符串中：Testname:“非HDL胆固醇”？您的预期输出不是有效的。非常感谢。这正是我想要的：

list1 = [
    ['Test Name', 'Results', 'Units', 'Bio. Ref. Interval'], 
    ['Cholesterol, Total', '243.00', 'mg/dL', '<200.00'], 
    ['Triglycerides', '365.00', 'mg/dL', '<150.00'], 
    ['HDL Cholesterol', '48.56', 'mg/dL', '>50.00'], 
    ['LDL Cholesterol, Calculated', '121.44', 'mg/dL', '<100.00'], 
    ['VLDL Cholesterol, Calculated *', '73.00', 'mg/dL', '<30.00'], 
    ['Non-HDL Cholesterol', '194', 'mg/dL', '<130']
]

# Output will be list of dictionary. Not dictionary of dictionary because we require key here.

keys = list1[0]

output_list = []
for item in list1[1:]:
    _tmp = {}
    for key, value in zip(keys, item):
        _tmp[key] = value
    output_list.append(_tmp)

print("output_list:", output_list)

output_list = [dict(zip(keys, item)) for item in list1[1:]]

print("output_list:", output_list)

my_list_of_dictionaries = [{k:i[list1[0].index(k)] for k in list1[0]} for i in list1[1:]]