Python 如何使用多种JSON格式?
我正在使用python脚本来提取、解析和格式化Twitter趋势JSON。特定于位置的格式将趋势嵌套在数组中:Python 如何使用多种JSON格式?,python,json,twitter,Python,Json,Twitter,我正在使用python脚本来提取、解析和格式化Twitter趋势JSON。特定于位置的格式将趋势嵌套在数组中: [ { "created_at": "2010-07-15T22:31:11Z", "trends": [ { "name": "trendy", "url": "http://search.twitter.com/search?q=trendy", "query": "trendy" }, .
[
{
"created_at": "2010-07-15T22:31:11Z",
"trends": [
{
"name": "trendy",
"url": "http://search.twitter.com/search?q=trendy",
"query": "trendy"
}, ...
而每日和每周json格式不:
{
"trends": {
"2011-01-14 15:20": [
{
"name": "#trendy",
"events": null,
"promoted_content": null,
"query": "#trendy"
},
我用这个python列出了趋势:
class trend:
#initialize a "trend" object with foo = trend(query,name ...)
def __init__(self, query, name, promoted_content, events, url):
self.query = query
self.name = name
self.promoted_content = promoted_content
self.events = events
self.url = url
class trending:
def __init__(self,api_url,title):
self.api_url = api_url
self.title = title
def get_trending(self):
import simplejson as json
import urllib2
trends_all = json.loads(urllib2.urlopen(self.api_url).read())
return trends_all
def list_trending(self):
trends_all = self.get_trending()
print "%s\n" % self.title
for x in trends_all[0]['trends']:
thistrend = trend(x['query'], x['name'], x['promoted_content'], x['events'], x['url'])
print "\t %s (%s) %s" %(thistrend.name, thistrend.url, thistrend.promoted_content)
这适用于第一种位置格式,但不适用于每日/每周格式。所以我想知道是否有一种聪明的方法来区分这两个JSON结构并重新构造它们,这样我就可以同时使用这两个结构。更通用的情况是带有列表的情况。 因为您只需要第一个元素,如果解析的对象是一个列表,则提取第一个值 在代码中,您可以简单地替换:
for x in trends_all[0]['trends']:
...
与
if isinstance(trends_all, list):
trends_all = trends_all[0]
for x in trends_all['trends']:
...