猜测日期格式python
我正在一个Python模块中编写一个方法,试图让用户更轻松地使用它。此方法实现在该日历中创建事件猜测日期格式python,python,exception,datetime,strptime,Python,Exception,Datetime,Strptime,我正在一个Python模块中编写一个方法,试图让用户更轻松地使用它。此方法实现在该日历中创建事件 def update_event(start_datetime=None, end_datetime=None, description=None): ''' Args: start_date: string datetime in the format YYYY-MM-DD or in RFC 3339 end_date: string datetime in the format YYY
def update_event(start_datetime=None, end_datetime=None, description=None):
'''
Args:
start_date: string datetime in the format YYYY-MM-DD or in RFC 3339
end_date: string datetime in the format YYYY-MM-DD or in RFC 3339
description: string with description (\n are transforrmed into new lines)
'''
如果用户指定开始日期或结束日期,则应进行检查,以确定日期是YYYY-MM-DD格式还是datetime RFC 3339格式
if (start_date is not None):
# Check whether we have an date or datetime value
# Whole day events are represented as YYYY-MM-DD
# Other events are represented as 2014-04-25T10:47:00.000-07:00
whole_day_event = False
try:
new_start_time = datetime.datetime.strptime(start_date,'YYYY-MM-DD')
# Here the event date is updated
try:
new_start_time = datetime.datetime.strptime(start_date,'%Y-%m-%dT%H:%M:%S%z')
#Here the event date is updated
except ValueError:
return (ErrorCodeWhatever)
except ValueError:
return (ErrorCodeWhatever)
这是一个很好的方法吗?我能以更好的方式查看我收到的日期吗?
谢谢 可用于尝试将字符串解析为datetime
对象
from dateutil.parser import parse
def update_event(start_datetime=None, end_datetime=None, description=None):
if start_datetime is not None:
new_start_time = parse(start_datetime)
return new_start_time
d = ['23/04/2014', '24-04-2013', '25th April 2014']
new = [update_event(i) for i in d]
for date in new:
print(date)
# 2014-04-23 00:00:00
# 2013-04-24 00:00:00
# 2014-04-25 00:00:00
可用于尝试将字符串解析为datetime
对象
from dateutil.parser import parse
def update_event(start_datetime=None, end_datetime=None, description=None):
if start_datetime is not None:
new_start_time = parse(start_datetime)
return new_start_time
d = ['23/04/2014', '24-04-2013', '25th April 2014']
new = [update_event(i) for i in d]
for date in new:
print(date)
# 2014-04-23 00:00:00
# 2013-04-24 00:00:00
# 2014-04-25 00:00:00
你应该
提出
错误,不要返回
错误。你完全正确,我只是在完成代码来发布问题你应该提出
错误,不要返回
错误。你完全正确,我只是在完成代码来发布问题谢谢!我不知道:)没问题,很高兴能帮上忙。如果你觉得我的回答对你有帮助,你可以。谢谢!我不知道:)没问题,很高兴能帮上忙。如果你觉得我的回答对你有帮助,你可以。