Python grep文件的每一行，并递增值

我有一个包含以下行的文件：

[tree]:1,"asdf"
[box]:2,"yuio"
[bee]:10,"rtyu"
[cup]:15,"bnmv"
[tree]:13,"asdf"

我希望输出是

[tree]:2,"asdf"
[box]:2,"yuio"
[bee]:10,"rtyu"
[cup]:15,"bnmv"
[tree]:14,"asdf"

所以我需要将[tree]值增加1。我需要一些方法来搜索每一行的[tree]，复制它旁边可能超过2位的数字，然后增加这个数字。我已经在Matlab中完成了这项工作，但速度非常慢，而且需要重写整个文件。我正在寻找一个更快的替代方案，比如bash脚本或者python中的一些东西。

试试这个：

def incrementKeys(infilepath, outfilepath, keys, incrementBy):
    with open(infilepath) as infile, open(outfilepath, 'w') as outfile:
        for line in infile:
            if any(line.startswith(key) for key in keys):
                k, tail = line.split(',')
                k, val = k.split(":")
                val = int(val)+incrementBy
                line = "%s:%d,%s\n" %(k, val, tail)
            outfile.write(line)

f = file("file.txt")
for l in f:
    if l[:6] == "[tree]":
        s = "".join([l[:l.find(":")+1], str(int(l[l.find(":")+1:l.find(",")])+1), l[l.find(","):]])
        print s

不要打印，而要对结果做任何你喜欢的事情。例如，您可以再次将其写入文件