Python 将文本文件转换为列表列表

我想将文本文件转换为以下格式：

0,0,0,0,0,0,0,
0,1,0,0,0,0,0,
0,2,0,0,0,0,0,
0,2,0,1,0,0,0,
2,1,0,2,1,0,0,
1,1,0,1,2,1,0,

进入一个列表。然而，我能得到的只是：

`[['0,0,0,0,0,0,0,'],
 ['0,1,0,0,0,0,0,'],
 ['0,2,0,0,0,0,0,'],
 ['0,2,0,1,0,0,0,'],
 ['2,1,0,2,1,0,0,'],
 ['1,1,0,1,2,1,0,']]`

但我不想在清单上加引号。有什么帮助吗

我的代码是：

while z!=0:
    y.append([f.readline().rstrip('\n')])
    z-=1  

试试这个：

y.append([int(n) for n in f.readline().rstrip('\n').split(',')[:-1]])

试试这个：

y.append([int(n) for n in f.readline().rstrip('\n').split(',')[:-1]])

---

在while循环中尝试以下操作：

y.append([int(i) for i in f.readline().rstrip('\n').split(',') if i])

---

在while循环中尝试以下操作：

y.append([int(i) for i in f.readline().rstrip('\n').split(',') if i])

---

您需要读取每一行，用逗号分隔，并将每个值解析为

int

values = []
with open("data.txt") as fic:
    for line in fic:
        line = line.rstrip(",\r\n")  
        row = list(map(int, line.split(",")))
        values.append(row)

# same as 
with open("data.txt") as fic:
    values = [list(map(int, line.rstrip(",\r\n").split(","))) for line in fic]

给你

[[0, 0, 0, 0, 0, 0, 0], 
 [0, 1, 0, 0, 0, 0, 0], 
 [0, 2, 0, 0, 0, 0, 0], 
 [0, 2, 0, 1, 0, 0, 0], 
 [2, 1, 0, 2, 1, 0, 0], 
 [1, 1, 0, 1, 2, 1, 0]]

---

您需要读取每一行，用逗号分隔，并将每个值解析为

int

values = []
with open("data.txt") as fic:
    for line in fic:
        line = line.rstrip(",\r\n")  
        row = list(map(int, line.split(",")))
        values.append(row)

# same as 
with open("data.txt") as fic:
    values = [list(map(int, line.rstrip(",\r\n").split(","))) for line in fic]

给你

[[0, 0, 0, 0, 0, 0, 0], 
 [0, 1, 0, 0, 0, 0, 0], 
 [0, 2, 0, 0, 0, 0, 0], 
 [0, 2, 0, 1, 0, 0, 0], 
 [2, 1, 0, 2, 1, 0, 0], 
 [1, 1, 0, 1, 2, 1, 0]]

---

你有引号是因为它们是字符串，你需要整数没有标记你有引号是因为它们是字符串，你需要整数没有标记