Python 如何将数据传递到django_表2'；s链接栏

我的urlconf代码段是：

url(r'^play/(?P<songid>\d+)', 'playid', name="playsongid")

我使用django-tables2库，它们的教程是[django-tables2][1]。 我的桌子是sinppet：

import django_tables2 as tables

class TestTable(tables.Table)
    links = tables.LinkColumn("playsongid", kwargs={"songid": ...})

“…”是我困惑的立场。如何在我的视图函数中将各种

songid

数据传递给它（此视图函数不是

playid

，它是另一个视图函数）？ 我希望django-tables2可以呈现如下数据：

def playid(request, songid):
    #do something

column
<a href="/play/1">aaa</a>
<a href="/play/2">bbb</a>
<a href="/play/3">ccc</a>

import django_tables2 as tables
from django_tables2.utils import Accessor

class TestTable(tables.Table)
    songid = tables.Column()
    links = tables.LinkColumn("playsongid", kwargs={"songid": Accessor("songid")})

列

---

---

终于我自己动手了！tables.py最后是这样的：

def playid(request, songid):
    #do something

column
<a href="/play/1">aaa</a>
<a href="/play/2">bbb</a>
<a href="/play/3">ccc</a>

import django_tables2 as tables
from django_tables2.utils import Accessor

class TestTable(tables.Table)
    songid = tables.Column()
    links = tables.LinkColumn("playsongid", kwargs={"songid": Accessor("songid")})

在我的视图函数中，我像这样向它传递数据

    playlist = conn.playlistinfo()
    table_data = []
    for info in playlist:
        tmp_dict = {"songid": info.id}
        tmp_dict["links"] = "%s - %s" % (get_attr(info, "artist"), get_attr(info, "title"))
        table_data.append(tmp_dict)
        del tmp_dict
    variables["table"] = PlaylistTable(table_data)  

---

终于我自己动手了！tables.py最后是这样的：

def playid(request, songid):
    #do something

column
<a href="/play/1">aaa</a>
<a href="/play/2">bbb</a>
<a href="/play/3">ccc</a>

import django_tables2 as tables
from django_tables2.utils import Accessor

class TestTable(tables.Table)
    songid = tables.Column()
    links = tables.LinkColumn("playsongid", kwargs={"songid": Accessor("songid")})

在我的视图函数中，我像这样向它传递数据

    playlist = conn.playlistinfo()
    table_data = []
    for info in playlist:
        tmp_dict = {"songid": info.id}
        tmp_dict["links"] = "%s - %s" % (get_attr(info, "artist"), get_attr(info, "title"))
        table_data.append(tmp_dict)
        del tmp_dict
    variables["table"] = PlaylistTable(table_data)  

---

现在我开始工作了！tables.py最后是这样的：

import django\u tables2作为来自django\u tables2的表。utils import Accessor class TestTable（tables.Table）links=tables.LinkColumn（“playsongid”，kwargs={“songid”：Accessor（“songid”）}

现在我让它开始工作了！tables.py最后是这样的：

import django_tables 2作为来自django_tables 2的表。utils import Accessor class TestTable（tables.Table）links=tables.LinkColumn（“playsongid”，kwargs={“songid”：Accessor（“songid”）}