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python或pyqt-检查鼠标按钮单击状态_Python_Mouse_Pyqt_Release_Click - Fatal编程技术网

python或pyqt-检查鼠标按钮单击状态

python或pyqt-检查鼠标按钮单击状态,python,mouse,pyqt,release,click,Python,Mouse,Pyqt,Release,Click,我需要检查鼠标按钮是否被点击或释放。 我正在使用pyqt——有没有办法在qt中检查鼠标按钮的释放状态,或者直接在python中检查鼠标按钮的释放状态 我知道pygame模块,但希望不必安装它。在PyQt4/doc/html/qt.html\MouseButton enum查看文档 Constant Value Qt.NoButton 0x00000000 Qt.LeftButton 0x00000001 Qt.RightButton 0x00000002 Qt.MidButton

我需要检查鼠标按钮是否被点击或释放。 我正在使用pyqt——有没有办法在qt中检查鼠标按钮的释放状态,或者直接在python中检查鼠标按钮的释放状态


我知道pygame模块,但希望不必安装它。

PyQt4/doc/html/qt.html\MouseButton enum查看文档

Constant    Value
Qt.NoButton 0x00000000
Qt.LeftButton   0x00000001
Qt.RightButton  0x00000002
Qt.MidButton    0x00000004
Qt.MiddleButton MidButton
Qt.XButton1 0x00000008
Qt.XButton2 0x00000010
一个简单的例子:

>>> from PyQt4 import QtCore, QtGui
>>> app=QtGui.QApplication([])
>>> mouse_state=app.mouseButtons()
>>> mouse_state==QtCore.Qt.NoButton
True
>>> int(mouse_state)
0