Python 使用'；搜索过滤器'；我在尝试搜索时出错

当我在api中使用搜索函数时，我得到一个错误，上面写着“无法将关键字‘q/c’解析到字段中。选项是：‘XXX’”。q或c取决于我所在的api页面。“c”代表我的选择，而“q”代表问题

from rest_framework import generics  
from . serializers import QuestionSerializer, ChoiceSerializer  
from django_filters.rest_framework import DjangoFilterBackend  
from rest_framework.filters import OrderingFilter, SearchFilter


from polls.models import Choice, Question


# need to create a view for each serializer class QuestionList(generics.ListAPIView):
    serializer_class = QuestionSerializer  # set the serializer
    queryset = Question.objects.all()  # set the query set to all the objects of that view
    filter_backends = (DjangoFilterBackend, OrderingFilter, SearchFilter)  # allows for filters
    filter_fields = {'id': ['gte', 'lte', 'exact'], 'pub_date': ['gte', 'lte']}
    ordering_fields = ('id', 'question_text', 'pub_date')
    search_fields = 'question_text'


class ChoiceList(generics.ListAPIView):
    serializer_class = ChoiceSerializer
    queryset = Choice.objects.all()
    filter_backends = (DjangoFilterBackend, OrderingFilter, SearchFilter)
    # trying to do greater than or less than filter fields stuff
    filter_fields = {'id': ['gte', 'lte', 'exact'], 'votes': ['gte', 'lte', 'exact']}
    ordering_fields = ('id', 'votes', 'choice_text', 'question',)
    search_fields = 'choice_text'

报告说：

search\u fields

属性应该是模型上文本类型字段的名称列表

您正在将字符串分配给两个

搜索\u字段

变量。将其更改为列表或元组，如下所示：

search_fields = ('question_text',)
search_fields = ('choice_text',)

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非常感谢你！我是个白痴哈哈。我感谢你的帮助！