Python uff通过etree不会破坏其他实现良好的应用程序解析数据,这可能会给正确使用解析器的应用程序带来问题(非常不可能)。 import xml.etree.cElementTree as ET import time import fileinput imp
uff通过etree不会破坏其他实现良好的应用程序解析数据,这可能会给正确使用解析器的应用程序带来问题(非常不可能)。Python uff通过etree不会破坏其他实现良好的应用程序解析数据,这可能会给正确使用解析器的应用程序带来问题(非常不可能)。 import xml.etree.cElementTree as ET import time import fileinput imp,python,regex,xml,elementtree,Python,Regex,Xml,Elementtree,uff通过etree不会破坏其他实现良好的应用程序解析数据,这可能会给正确使用解析器的应用程序带来问题(非常不可能)。 import xml.etree.cElementTree as ET import time import fileinput import re ts = str(int(time.time())) modifiedline ='' for line in fileinput.input("singleoutbound.xml"): line = re.sub('
import xml.etree.cElementTree as ET
import time
import fileinput
import re
ts = str(int(time.time()))
modifiedline =''
for line in fileinput.input("singleoutbound.xml"):
line = re.sub('OrderName=".*"','OrderName="'+ts+'"', line)
line = re.sub('OrderNo=".*"','OrderNo="'+ts+'"', line)
line = re.sub('ShipmentNo=".*"','ShipmentNo="'+ts+'"', line)
line = re.sub('TrackingNo=".*"','TrackingNo="'+ts+'"', line)
line = re.sub('WaveKey=".*"','WaveKey="'+ts+'"', line)
modifiedline=modifiedline+line
import xml.etree.cElementTree as ET
import time
ts = str(int(time.time()))
doc = ET.parse('singleoutbound.xml')
for elem in doc.iterfind('//*'):
if 'OrderName' in elem.attrib:
elem.attrib['OrderName'] = ts
if 'OrderNo' in elem.attrib:
elem.attrib['OrderNo'] = ts
if 'ShipmentNo' in elem.attrib:
elem.attrib['ShipmentNo'] = ts
if 'TrackingNo' in elem.attrib:
elem.attrib['TrackingNo'] = ts
if 'WaveKey' in elem.attrib:
elem.attrib['WaveKey'] = ts
doc.write('singleoutbound_2.xml')
import xml.etree.cElementTree as ET
import time
ts = str(int(time.time()))
doc = ET.parse('singleoutbound.xml')
for elem in doc.iterfind('//*[@OrderName]'):
elem.attrib['OrderName'] = ts
# and so on
doc.write('singleoutbound_2.xml')