Python 在动态添加值后使用join打印

我有以下数据

r = ('P','A','A','P')
newval = 'Q'
newval2 = 'Z'

我要做的是将

r

的值与newval一起打印。 但为何失败：

   print ",".join([r[0:4],newval,newval2])

所需输出为：

P,A,A,P,Q,Z

---

r

是tuple类型，只接受单级iterable。因此，可以将其他数据连接为元组，如下所示

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
print ",".join(r + (newval,) + (newval2,))
# P,A,A,P,Q,Z

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
from itertools import chain
print ",".join(chain(r, newval, newval2))

或者，您可以像这样使用

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
print ",".join(r + (newval,) + (newval2,))
# P,A,A,P,Q,Z

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
from itertools import chain
print ",".join(chain(r, newval, newval2))

---

r

是tuple类型，只接受单级iterable。因此，可以将其他数据连接为元组，如下所示

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
print ",".join(r + (newval,) + (newval2,))
# P,A,A,P,Q,Z

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
from itertools import chain
print ",".join(chain(r, newval, newval2))

或者，您可以像这样使用

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
print ",".join(r + (newval,) + (newval2,))
# P,A,A,P,Q,Z

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
from itertools import chain
print ",".join(chain(r, newval, newval2))

---

r

是tuple类型，只接受单级iterable。因此，可以将其他数据连接为元组，如下所示

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
print ",".join(r + (newval,) + (newval2,))
# P,A,A,P,Q,Z

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
from itertools import chain
print ",".join(chain(r, newval, newval2))

或者，您可以像这样使用

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
print ",".join(r + (newval,) + (newval2,))
# P,A,A,P,Q,Z

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
from itertools import chain
print ",".join(chain(r, newval, newval2))

---

r

是tuple类型，只接受单级iterable。因此，可以将其他数据连接为元组，如下所示

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
print ",".join(r + (newval,) + (newval2,))
# P,A,A,P,Q,Z

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
from itertools import chain
print ",".join(chain(r, newval, newval2))

或者，您可以像这样使用

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
print ",".join(r + (newval,) + (newval2,))
# P,A,A,P,Q,Z

r, newval, newval2 = ('P','A','A','P'), 'Q', 'Z'
from itertools import chain
print ",".join(chain(r, newval, newval2))

---

我想我会将它们连接为两个列表：

>>> print ",".join(list(r) + [newval, newval2])
P,A,A,P,Q,Z

---

我想我会将它们连接为两个列表：

>>> print ",".join(list(r) + [newval, newval2])
P,A,A,P,Q,Z

---

我想我会将它们连接为两个列表：

>>> print ",".join(list(r) + [newval, newval2])
P,A,A,P,Q,Z

---

我想我会将它们连接为两个列表：

>>> print ",".join(list(r) + [newval, newval2])
P,A,A,P,Q,Z