Python TypeError:+；的操作数类型不受支持：'；int'；和'；str'；错误

我的代码有问题，它说

TypeError:不支持+：“int”和“str”的操作数类型

我不知道为什么。导致这种情况的代码区域如下所示，所有帮助都将不胜感激：D*编辑错误似乎是因为输入选项而发生的，如果这有任何帮助的话

Score1 = str(input("what did the first person get in their test the first     time?"))
Score2 = str(input("what did the first person get in their test the second  time?"))
Score3 = str(input("what did the first person get in their test the third time?"))

Score4 = str(input("what did the second person get in their test the first time?"))
Score5 = str(input("what did the second person get in their test the second time?"))
Score6 = str(input("what did the second person get in their test the third time?"))


Score7 = str(input("what did the third person get in their test the first time?"))
Score8 = str(input("what did the third person get in their test the second time?"))
Score9 = str(input("what did the third person get in their test the third time?"))


P1S = [Score1, Score2, Score3]
P2S = [Score4, Score5, Score6]
P3S = [Score7, Score8, Score9]



print ("here are the scores of",Name1,",well done") # defines scores
print(P1S)
print ("here is the average score of",Name1,",Well Done") # makes average of  scores
print(sum(P1S)/float(len(P1S)))

print ("here are the scores of",Name2,",well done") # defines scores
print(P2S)
print ("here is the average score of",Name2,",Well Done") # makes average of scores
print(sum(P2S)/float(len(P2S)))

print ("here are the scores of",Name3,",well done") # defines scores
print(P3S)
print ("here is the average score of",Name3,",Well Done") # makes average of scores
print(sum(P3S)/float(len(P3S)))

您明确地注意用户输入的内容是字符串：

Score1 = str(input("what did the first person get in their test the first     time?"))

---

如果将

str（）

替换为

int（）

或

float（）

（取决于您预期的输入），您的问题应该会消失，因为您会得到一个数字类型，而不是

str

ing。

将字符串默认输入转换为整数，以便您可以计算平均分数：

Score1 = int(input("what did the first person get in their test the first time?"))

---

您还可以在计算分数时使用map

print ("here are the scores of",Name1,",well done") # defines scores
print(P1S)
print ("here is the average score of",Name1,",Well Done") # makes average of  scores
print(sum(map(int,P1S))/float(len(P1S)))

print ("here are the scores of",Name2,",well done") # defines scores
print(P2S)
print ("here is the average score of",Name2,",Well Done") # makes average of scores
print(sum(map(int,P2S))/float(len(P2S)))

print ("here are the scores of",Name3,",well done") # defines scores
print(P3S)
print ("here is the average score of",Name3,",Well Done") # makes average of scores
print(sum(map(int,P3S))/float(len(P3S)))

---

您还可以告诉我您是如何提供输入的。

我认为您必须将

分数

输入转换为int，它们最初被解释为字符串。您能解释一下您希望它做什么吗？另外，您能将代码缩减到最小以显示eror吗？我想要它，这样我就可以使用我的输入作为数字来处理sumI，现在可以对这个问题进行回溯（最后一次调用）：文件“\\CUR-FSM\10brierleye$\Computing CA 2\task 3 average.py”，第57行，Stu3AVG=（sum（Score3）/float（len（Score3）））#定义平均TypeError:“int”对象不是iterablethat行不出现在您发布的代码中。实际上，您可以a）提出一个新问题，或者b）尝试了解错误的原因。编程就是要理解问题，而您目前所做的只是不断运行StackOverflow来报告错误。我建议你认真阅读错误。它确实说明了问题所在。我会尝试向您展示我的全部代码，但对于回复来说太长了，基本上我输入了一个名称和一些值来创建输入分数的平均值，将名称按字母顺序排序，并将平均值按从高到低的数字顺序排序，然而，它说输入的整数不可iterable，我也不知道为什么：李一直收到这样的信息：“int”对象不可iterable，你可以评分吗？发布您的更新代码以进行调试。您使用的是Python 2还是Python 3？Score7=int（输入（“第三人第一次在测试中得到了什么？”））Score8=int（输入（“第三人第二次在测试中得到了什么？”））Score9=int（输入（“第三人第三次在测试中得到了什么？”）P1S=[Score1，Score2，Score3]P2S=[Score4，Score5，Score6]P3S=[Score7，Score8，Score9]打印（“这里是”Name1“的分数，做得好”）#定义分数打印（P1S）打印（“这里是”Name1“的平均分数，做得好”）#使分数打印平均（总和（P1S）/浮点（len（P1S）））Python3.2我相信69我是通过手动输入提供输入的，尽管我将输入定义为一个整数（因为我需要在代码后面的等式中使用它），但我仍然得到Int是不可接受的问题行号是56，错误是INT不可iterable，我不知道为什么，因为当我设置值时它工作，但现在我以某种方式添加到输入值中，它被破坏了