Python 随机_状态并一起洗牌

在这里，我对同时使用

random\u state

和

shuffle

感到有些困惑。我想分割数据，而不洗牌它。在我看来，当我将shuffle设置为False时，无论我为random_state选择的数字是多少，我都有相同的输出（random_state 42或2、7、17等的分割是相同的）。为什么?

但是，如果shuffle是真的，那么对于不同的随机状态，我有不同的输出（分割），这是有意义的

X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.25,random_state=42)

---

如果将

shuffle

设置为False，

train\u test\u split

只按原始顺序读取数据。因此，完全忽略参数

random_state

例如：

X = [k for k in range(0, 50)] # create array with numbers ranging from 0 to 49
y = X # just for testing
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.25, random_state=42, shuffle=False)

print(X_train) // prints [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36]

一旦将

shuffle

设置为True，

random\u state

将用作随机数生成器的种子。结果，您的数据集被随机分为训练集和测试集

随机_状态=42的示例：

X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.25, random_state=42, shuffle=True)

print(X_train) // prints [8, 3, 6, 41, 46, 47, 15, 9, 16, 24, 34, 31, 0, 44, 27, 33, 5, 29, 11, 36, 1, 21, 2, 43, 35, 23, 40, 10, 22, 18, 49, 20, 7, 42, 14, 28, 38]

随机_状态=44的示例：

X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.25, random_state=44, shuffle=True)

print(X_train) // prints [13, 11, 2, 12, 34, 41, 30, 16, 39, 28, 24, 8, 18, 9, 4, 10, 0, 19, 21, 29, 14, 1, 48, 38, 7, 43, 25, 22, 23, 42, 46, 49, 32, 3, 45, 35, 20]

X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.25, random_state=44, shuffle=True)

print(X_train) // prints [13, 11, 2, 12, 34, 41, 30, 16, 39, 28, 24, 8, 18, 9, 4, 10, 0, 19, 21, 29, 14, 1, 48, 38, 7, 43, 25, 22, 23, 42, 46, 49, 32, 3, 45, 35, 20]