在不同的python字典项中迭代相同的键

我有一本复杂的字典，看起来像这样

{"Div 4 A Herrar": {
    "0": {"convertedTime": "86", "awayScore": "0", "homeTeam": "SKIF Semberija", "homeScore": "0", "awayTeam": "Floda BoIF", "time": "00:00", "events": []}, 
    "1": {"convertedTime": "40", "awayScore": "0", "homeTeam": "Partille IF FK ", "homeScore": "0", "awayTeam": "Kode IF", "time": "01:00", "events": []}, 
    "2": {"convertedTime": "", "awayScore": "0", "homeTeam": "IK Kongah\u00e4lla", "homeScore": "0", "awayTeam": "Romelanda UF", "time": "02:00", "events": []}, 
    "3": {"convertedTime": "", "awayScore": "0", "homeTeam": "IK Virgo", "homeScore": "0", "awayTeam": "United Africa FC", "time": "03:00", "events": []}, 
    "4": {"convertedTime": "", "awayScore": "0", "homeTeam": "Hisingsbacka FC", "homeScore": "0", "awayTeam": "Guldhedens IK", "time": "04:00", "events": []}, 
    "5": {"convertedTime": "", "awayScore": "0", "homeTeam": "IF Warta", "homeScore": "0", "awayTeam": "Bergums IF", "time": "05:00", "events": []}
    }
 "Div 5 A Herrar": {
    "0": {"convertedTime": "86", "awayScore": "0", "homeTeam": "SKIF Semberija", "homeScore": "0", "awayTeam": "Floda BoIF", "time": "00:00", "events": []}, 
    "1": {"convertedTime": "40", "awayScore": "0", "homeTeam": "Partille IF FK ", "homeScore": "0", "awayTeam": "Kode IF", "time": "01:00", "events": []}, 
    "2": {"convertedTime": "", "awayScore": "0", "homeTeam": "IK Kongah\u00e4lla", "homeScore": "0", "awayTeam": "Romelanda UF", "time": "02:00", "events": []}, 
    "3": {"convertedTime": "", "awayScore": "0", "homeTeam": "IK Virgo", "homeScore": "0", "awayTeam": "United Africa FC", "time": "03:00", "events": []}, 
    "4": {"convertedTime": "", "awayScore": "0", "homeTeam": "Hisingsbacka FC", "homeScore": "0", "awayTeam": "Guldhedens IK", "time": "04:00", "events": []}, 
    "5": {"convertedTime": "", "awayScore": "0", "homeTeam": "IF Warta", "homeScore": "0", "awayTeam": "Bergums IF", "time": "05:00", "events": []}
    }
}

还有一些条目，但由于您了解了词典的结构，因此与此无关

---

现在我需要做的是遍历这个字典中的所有时间键，因为我需要更改它们的值。这意味着它必须遍历“div4a Herrar”中的6个时间键/对值和“div5a Herrar”中的6个时间键/对值。我到底怎么才能完成这样的事情呢？我完全迷路了

如果你介绍的结构保持不变，你可以使用以下两种方法之一。否则，您将不得不创建一个递归函数

dict_of_herrars = {
    #...
}  

方法1 方法2 演示 代码： 输出：

---

要获得时间值，请执行以下操作：

for key1 in dict:
    for key2 in dict[key1]:
       dict[key1][key2]['time'] = 'newTime'

---

要清楚：您需要访问整个词典中每个词典的所有

convertedTime

键。您知道如何访问其中一个词典中的所有

convertedTime

键吗？你知道如何访问每一本字典吗？Wonderufl，我不知道我能写key1，它会自动知道。谢谢u make life ez for Me当你在dict中迭代时，你总是会得到keyvalues，提前，当你在dict中迭代

键、值时，你会得到键和值项。
def iter_time(dict_of_herrars):
    # herrar = "Div 4 A Herrar", etc
    for herrar, herrar_dict in dict_of_herrars.items():
        # game = "0","1",etc
        for game, game_dict in herrar_dict.items():
            def change_time(new_time,game_dict=game_dict):
                game_dict["time"]=newtime
            yield change_time

for change_time in iter_time(dict_of_herrars):
    change_time("13:37")

d = {"Div 4 A Herrar" : {
    "0": {"convertedTime": "86", "awayScore": "0", "homeTeam": "SKIF Semberija", "homeScore": "0", "awayTeam": "Floda BoIF", "time": "00:00", "events": []}, 
    "1": {"convertedTime": "40", "awayScore": "0", "homeTeam": "Partille IF FK ", "homeScore": "0", "awayTeam": "Kode IF", "time": "01:00", "events": []}, 
    "2": {"convertedTime": "", "awayScore": "0", "homeTeam": "IK Kongah\\u00e4lla", "homeScore": "0", "awayTeam": "Romelanda UF", "time": "02:00", "events": []}, 
    "3": {"convertedTime": "", "awayScore": "0", "homeTeam": "IK Virgo", "homeScore": "0", "awayTeam": "United Africa FC", "time": "03:00", "events": []}, 
    "4": {"convertedTime": "", "awayScore": "0", "homeTeam": "Hisingsbacka FC", "homeScore": "0", "awayTeam": "Guldhedens IK", "time": "04:00", "events": []}, 
    "5": {"convertedTime": "", "awayScore": "0", "homeTeam": "IF Warta", "homeScore": "0", "awayTeam": "Bergums IF", "time": "05:00", "events": []}
    },
 "Div 5 A Herrar" : {
    "0": {"convertedTime": "86", "awayScore": "0", "homeTeam": "SKIF Semberija", "homeScore": "0", "awayTeam": "Floda BoIF", "time": "00:00", "events": []}, 
    "1": {"convertedTime": "40", "awayScore": "0", "homeTeam": "Partille IF FK ", "homeScore": "0", "awayTeam": "Kode IF", "time": "01:00", "events": []}, 
    "2": {"convertedTime": "", "awayScore": "0", "homeTeam": "IK Kongah\\u00e4lla", "homeScore": "0", "awayTeam": "Romelanda UF", "time": "02:00", "events": []}, 
    "3": {"convertedTime": "", "awayScore": "0", "homeTeam": "IK Virgo", "homeScore": "0", "awayTeam": "United Africa FC", "time": "03:00", "events": []}, 
    "4": {"convertedTime": "", "awayScore": "0", "homeTeam": "Hisingsbacka FC", "homeScore": "0", "awayTeam": "Guldhedens IK", "time": "04:00", "events": []}, 
    "5": {"convertedTime": "", "awayScore": "0", "homeTeam": "IF Warta", "homeScore": "0", "awayTeam": "Bergums IF", "time": "05:00", "events": []}
    }
}

for i in d:
    for j in d[i]:
        for k in d[i][j]:
            if k == "time":
                print "Original Time: ", d[i][j][k]
                d[i][j][k] = "something"
                print "Changed to: ", d[i][j][k]

Original Time:  01:00
Changed to:  something
Original Time:  00:00
Changed to:  something
Original Time:  03:00
Changed to:  something
Original Time:  02:00
Changed to:  something
Original Time:  05:00
Changed to:  something
Original Time:  04:00
Changed to:  something
Original Time:  01:00
Changed to:  something
Original Time:  00:00
Changed to:  something
Original Time:  03:00
Changed to:  something
Original Time:  02:00
Changed to:  something
Original Time:  05:00
Changed to:  something
Original Time:  04:00
Changed to:  something

for key1 in dict:
    for key2 in dict[key1]:
       dict[key1][key2]['time'] = 'newTime'