Python 即使更改了字典外的同一变量,字典内的变量值也保持不变。为什么?
我有一本字典Python 即使更改了字典外的同一变量,字典内的变量值也保持不变。为什么?,python,dictionary,variable-assignment,Python,Dictionary,Variable Assignment,我有一本字典餐厅,希望根据用户输入的日期,在餐厅的嵌套列表中更改营业时间和营业时间的值 opening_time=0 closing_time=0 ##snippet of the dictionary restaurants={"Macdonald's":\ \ [{"Monday":[700,2400],\ "Tuesday":[700,2400],\ "Wednesday":
餐厅
,希望根据用户输入的日期,在餐厅
的嵌套列表中更改营业时间
和营业时间
的值
opening_time=0
closing_time=0
##snippet of the dictionary
restaurants={"Macdonald's":\
\
[{"Monday":[700,2400],\
"Tuesday":[700,2400],\
"Wednesday":[700,2400],\
"Thursday":[700,2400],\
"Friday":[700,2400],\
"Saturday":[700,2400],\
"Sunday":[1000,2200]},\
\
"Block XXX, #01-XX",\
"Fast food restaurant known for its all round excellent menu.",\
\
["Breakfast",[opening_time,1100],\
{"Egg McMuffin":"$1",\
"Hotcakes":"$1",\
"Big Breakfast":"$1"}],\
["Lunch/Dinner",[1100,closing_time],\
{"Double Cheeseburger":"$3.20",\
"McChicken":"$3.95",\
"Big Mac":"$4.70",\
"Chicken McNuggets (6pcs)":"$4.95",\
"McWings":"$4.95"}],\
["All Day",[opening_time,closing_time],\
{"Fillet-O-Fish":"$4.60",\
"Corn Cup":"$1.95"}]]}
我希望代码循环并打印所有餐厅和菜单,同时指示用户输入的时间内是否可以使用所述餐厅和菜单
for key in restaurants: #key refers to restaurant name
print("","",sep='\n')
if day_now in restaurants.get(key)[0].keys(): #check if restaurant is open on that day
opening_time=restaurants.get(key)[0][day_now][0] #set opening and closing hours to those on that day
closing_time=restaurants.get(key)[0][day_now][1]
if time_now>=opening_time and time_now<closing_time: #check if restaurant is open within that time period
status="Open"
open_restaurants.update(restaurants)
print(key,"Status: "+status,"Opening Hours Today:"+str(opening_time)+" to "+str(closing_time),\
"Location: "+restaurants.get(key)[1],"Description: "+restaurants.get(key)[2],sep='\n')
for i in range(3, len(restaurants.get(key))): #goes through the menus the restaurant has
print(restaurants.get(key)[i][1][0]) #prints 0
print(restaurants.get(key)[i][1][1]) #prints 0
if time_now>=restaurants.get(key)[i][1][0] and time_now<restaurants.get(key)[i][1][1]: #check if menu have
print("")
print(restaurants.get(key)[i][0]+" Menu: Available","Item: Cost:",sep='\n')
for item in restaurants.get(key)[i][2].keys():
print(item, restaurants.get(key)[i][2][item],sep=' ')
else:
print("")
print(restaurants.get(key)[i][0]+" Menu: Unavailable","Item: Cost:", sep='\n')
for item in restaurants.get(key)[i][2].keys():
print(item, restaurants.get(key)[i][2][item],sep=' ')
else:
closed_restaurants.update(restaurants)
status="Closed"
print(key,"Status: "+status,"Opening Hours Today:"+str(opening_time)+" to "+str(closing_time),\
"Location: "+restaurants.get(key)[1],"Description: "+restaurants.get(key)[2], sep='\n')
else:
closed_restaurants.update(restaurants)
status="Closed"
print(key,"Status: "+status,"Opening Hours Today:"+str(opening_time)+" to "+str(closing_time),\
"Location: "+restaurants.get(key)[1],"Description: "+restaurants.get(key)[2], sep='\n')
print(opening_time) #prints the correct opening and closing hours
print(closing_time)
餐厅钥匙:#钥匙指餐厅名称
打印(“,”,sep='\n')
如果您现在在餐厅。get(key)[0]。key():#检查餐厅当天是否营业
营业时间=餐厅。获取(键)[0][day_now][0]#将营业和关门时间设置为当天的营业和关门时间
关门时间=餐厅。获取(键)[0][day\u now][1]
如果time\u now>=开业时间和time\u now=餐厅。get(key)[i][1][0]和time\u now让我们用这个简单的例子来说明你的假设哪里是错误的:
var = 1
lst = [var]
var = 2
print(lst)
该打印什么,[1]
或[2]
?它将打印[1]
。这里的不是变量引用列表,而是整数列表。您获取值var
had,并将其放入列表中。一份,如果你想的话
这个怎么样
a = 1
b = a
a = 2
在此之后,b
仍然是1
。您将在存储a
的位置写入的内容取出,并将其放入存储b
的位置
您需要实际更新字典中的值,仅更新开放时间是不够的
我不确定您希望在这里输出什么。您认为代码的哪一部分应该改变您在print语句中获得的输出,您希望它打印什么?