Python 在邮件打开时获取消息
根据下面的代码,我正在发送带有一些信息的邮件。在这里,当他/她打开邮件时,我需要将邮件发送到我的邮件id。 如何在Python中实现这一点Python 在邮件打开时获取消息,python,email,Python,Email,根据下面的代码,我正在发送带有一些信息的邮件。在这里,当他/她打开邮件时,我需要将邮件发送到我的邮件id。 如何在Python中实现这一点 def Data(request): templateName = "sendmail.html" mapDictionary = {'fromMail': "xxxx.xxxx@gmail.com", 'password': "xxxxx", 'toMail': "yyyyy.yyyy@gmail.com@gmail.com",
def Data(request):
templateName = "sendmail.html"
mapDictionary = {'fromMail': "xxxx.xxxx@gmail.com", 'password': "xxxxx", 'toMail': "yyyyy.yyyy@gmail.com@gmail.com",
"subject": "New Trip Confirmation", 'username': 'Ramesh','trip_start_date' : '2014-02-10',
'trip_start_place' : 'Visak', 'trip_start_time' : '11:00 AM', "templateName" : templateName
}
print ("call send mail from processNewTripData...")
return sendmail(request, mapDictionary)
def sendmail(request, mapDictionary):
try:
server = smtplib.SMTP('smtp.gmail.com',587)
server.starttls()
server.login(mapDictionary["fromMail"],mapDictionary["password"])
context = Context(mapDictionary)
html_content = render_to_string(mapDictionary["templateName"], context)
#text_content = "This is Confirmation mail"
msg = MIMEText(html_content,'html')
msg['Subject'] = mapDictionary["subject"]
server.sendmail(mapDictionary["fromMail"], mapDictionary['toMail'], msg.as_string())
to_json = {'result' : "True"}
return HttpResponse(simplejson.dumps(to_json), content_type='application/json')
except Exception as e:
print str(e)
to_json = {'result' : "False"}
return HttpResponse(simplejson.dumps(to_json), content_type='application/json')
请尝试添加此标题:
Disposition-Notification-To: "User" <user@user.com>
处置通知:“用户”
读者可能需要确认您是否收到了回复。另外,添加服务器提供的html内容也可以作为识别邮件已被读取的选项
您应该能够使用这些行中的任何一行来完成此操作
msg['Disposition-Notification-To'] = '"User" <user@user.com>'
msg['Disposition-Notification-To'] = 'user@user.com'
msg['Disposition-Notification-To']='“User”'
msg['Disposition-Notification-To']='user@user.com'
是否有示例代码?如何使用处置通知:“用户”添加了最可能的示例。