Python 多个编程单击事件的意外行为
我正在尝试使用PyQt5制作一个Tic-Tac-Toe用户界面。提供了三种模式 人与人 人类vs.人工智能 人工智能vs.人工智能游戏 所有模式都非常好,除了在模式3中,两个AI相互对抗,UI将开始加载并显示最终结果,而不是刷新每个回合的中间步骤,直到游戏开始,这是我所期望和首选的。我怎样才能做到呢?谢谢大家! 下面是我的代码:Python 多个编程单击事件的意外行为,python,qt,pyqt,pyqt5,Python,Qt,Pyqt,Pyqt5,我正在尝试使用PyQt5制作一个Tic-Tac-Toe用户界面。提供了三种模式 人与人 人类vs.人工智能 人工智能vs.人工智能游戏 所有模式都非常好,除了在模式3中,两个AI相互对抗,UI将开始加载并显示最终结果,而不是刷新每个回合的中间步骤,直到游戏开始,这是我所期望和首选的。我怎样才能做到呢?谢谢大家! 下面是我的代码: class TicTacToeUI(QtWidgets.QWidget): icons = ['icons/x-mark.png', 'icons/hollow
class TicTacToeUI(QtWidgets.QWidget):
icons = ['icons/x-mark.png', 'icons/hollow-circle.png']
def __init__(self, parent=None):
super().__init__(parent)
self.setWindowTitle("TicTacToe")
self.setStyleSheet('background-color: #D7CCC8;')
# Players
self._players_selector = QtWidgets.QGridLayout()
self._players = list()
for p in range(2):
label = QtWidgets.QLabel('Player {:}'.format(p))
selectbox = QtWidgets.QComboBox()
selectbox.setFixedHeight(24)
selectbox.addItems(list(PLAYERS.keys()))
self._players_selector.addWidget(label, 0, p)
self._players_selector.addWidget(selectbox, 1, p)
self._players.append(selectbox)
self._grid = QtWidgets.QGridLayout()
self._gameboard_buttons = dict()
for i in range(self.m):
for j in range(self.n):
btn = self.create_gameboard_button(row=i, col=j)
self._grid.addWidget(btn, i, j)
self._gameboard_buttons.update({(i, j): btn})
self._message_box = QtWidgets.QLabel('', parent=self)
self._restart_button = QtWidgets.QPushButton('Start', parent=self)
self._restart_button.setFixedHeight(32)
self._restart_button.clicked.connect(self.restart)
# Layout
self._layout = QtWidgets.QVBoxLayout()
self._layout.addLayout(self._players_selector)
self._layout.addLayout(self._grid)
self._layout.addWidget(self._message_box)
self._layout.addWidget(self._restart_button)
self.setLayout(self._layout)
# The game
self._game = TicTacToe()
self._started = False
def create_gameboard_button(self, row, col):
btn = TicTacToeUIButton('', parent=self, style_sheet='background-color: #D7CCC8;')
btn.setFixedSize(64, 64)
btn.clicked.connect(functools.partial(self.click, row, col))
return btn
def click(self, row, col):
if not self._started:
pass
elif self._game.is_ended:
pass
else:
btn = self._gameboard_buttons.get((row, col))
if btn is not None:
if btn.is_occupied:
msg = 'It is occupied. Please select another one.'
self._message_box.setText(msg)
else:
player = self._game.turn_player
# Icon appearance
for _, b in self._gameboard_buttons.items():
b.remove_border()
btn.setIcon(QtGui.QIcon(self.icons[player]))
btn.setIconSize(QtCore.QSize(48, 48))
btn.add_border('border: 1px solid #FF0000;')
btn.occupied_player = player
# Check result
self._game.move(row=row, col=col, player=player)
if self._game.winner is not None:
if self._game.winner == -1:
msg = 'Draw. What a game!'
else:
msg = 'Player {:} won. Congratulations!'
msg = msg.format(self._game.winner)
else:
msg = ''
self._message_box.setText(msg)
# Next turn
if self._game.is_ended:
pass
else:
self._game.players[self._game.turn_player].decide_ui(self)
def reset(self):
self._started = True
self._game.reset()
self._game.player0 = PLAYERS.get(self._players[0].currentText())
self._game.player1 = PLAYERS.get(self._players[1].currentText())
self._restart_button.setText('Restart')
self._message_box.setText('')
for _, btn in self._gameboard_buttons.items():
btn.reset()
if self._game.player0.is_ai:
self._game._player0.decide_ui(self)
def restart(self):
self.reset()
一些注意事项:
游戏将在点击“开始”/“重新启动”按钮后立即开始,玩家(无论是人类还是AI)将根据他们的判断/算法点击游戏板按钮
人类自己什么都不做,而
SomeAI.decision\u用户将根据某些算法单击游戏板按钮
TictaToe是一个存储游戏板矩阵和获胜标准的对象
如果您对玩游戏感兴趣,可以下载整套代码。为了更好地了解整个过程,我下载了完整的应用程序 因此,在运行时,AI会让主进程保持忙碌状态,而Qt事件永远不会被处理,UI上也不会绘制任何内容 最简单的解决方案是调用每个回合,如下所示:
def click(self, row, col):
# "click" code
QtWidgets.qApp.processEvents()
# Next turn
if self._game.is_ended:
pass
else:
self._game.players[self._game.turn_player].decide_ui(self)
这将处理所有未决事件,同时将显示一个动作。您可能需要降低AI完成游戏的速度。您可以使用QTimer类进行实验。@Crispin我的一些AI每回合可能需要1-2秒,但加载几秒钟后,最终结果将直接显示出来。中间的部分看不见。