Python 熊猫或蟒蛇相当于tidyr complete
我有如下数据:Python 熊猫或蟒蛇相当于tidyr complete,python,python-3.x,pandas,Python,Python 3.x,Pandas,我有如下数据: library("tidyverse") df <- tibble(user = c(1, 1, 2, 3, 3, 3), x = c("a", "b", "a", "a", "c", "d"), y = 1) df # user x y # 1 1 a 1 # 2 1 b 1 # 3 2 a 1 # 4 3 a 1 # 5 3 c
library("tidyverse")
df <- tibble(user = c(1, 1, 2, 3, 3, 3), x = c("a", "b", "a", "a", "c", "d"), y = 1)
df
# user x y
# 1 1 a 1
# 2 1 b 1
# 3 2 a 1
# 4 3 a 1
# 5 3 c 1
# 6 3 d 1
我希望“完成”数据帧,以便每个用户
都有一条记录,记录每个可能的x
,默认y
填充设置为0
这在R(tidyverse/tidyr)中有点微不足道:
pandas/python中是否有一个完整的等价物可以产生相同的结果?您可以通过以下方式使用:
或++:
现在,在python中使用这些
dplyr
/tidyr
API非常容易:
>>从datar.all导入f、c、TIBLE、完整、嵌套
>>>df=tibble(用户=c(1,1,2,3,3),x=c(“a”,“b”,“a”,“a”,“c”,“d”),y=1)
>>>df>>完成(嵌套(f.user),x=c(“a”、“b”、“c”、“d”),填充={'y':0})
用户x y
01A1.0
1b1.0
21 c0.0
31 d 0.0
4.2 a 1.0
52B0.0
6 2 c 0.0
7.2 d 0.0
8.3 a 1.0
93B0.0
103C1.0
11三维1.0
我是这个包裹的作者。如果您有任何问题,请随时提交问题
import pandas as pd
df = pd.DataFrame({'user':[1, 1, 2, 3, 3, 3], 'x':['a', 'b', 'a', 'a', 'c', 'd'], 'y':1})
df %>%
complete(nesting(user), x = c("a", "b", "c", "d"), fill = list(y = 0))
# user x y
# 1 1 a 1
# 2 1 b 1
# 3 1 c 0
# 4 1 d 0
# 5 2 a 1
# 6 2 b 0
# 7 2 c 0
# 8 2 d 0
# 9 3 a 1
# 10 3 b 0
# 11 3 c 1
# 12 3 d 1
df = df.set_index(['user','x'])
mux = pd.MultiIndex.from_product([df.index.levels[0], df.index.levels[1]],names=['user','x'])
df = df.reindex(mux, fill_value=0).reset_index()
print (df)
user x y
0 1 a 1
1 1 b 1
2 1 c 0
3 1 d 0
4 2 a 1
5 2 b 0
6 2 c 0
7 2 d 0
8 3 a 1
9 3 b 0
10 3 c 1
11 3 d 1
df = df.set_index(['user','x'])['y'].unstack(fill_value=0).stack().reset_index(name='y')
print (df)
user x y
0 1 a 1
1 1 b 1
2 1 c 0
3 1 d 0
4 2 a 1
5 2 b 0
6 2 c 0
7 2 d 0
8 3 a 1
9 3 b 0
10 3 c 1
11 3 d 1