Python 破坏由XOR加密的文本的密钥
我试图用Python编写自己的XOR破解程序。我只是尝试了一个非常简单的例子:Python 破坏由XOR加密的文本的密钥,python,python-3.x,cryptography,xor,Python,Python 3.x,Cryptography,Xor,我试图用Python编写自己的XOR破解程序。我只是尝试了一个非常简单的例子: THE MONEY IS BENEATH THE FLOOR BOARDS ENIGMAENIGMAENIGMAENIGMAENIGMAENIGMAE 但它总是返回空的内容(b'\x00\x00\x00\x00\x00\x00\x…。) 我认为我在获取密钥和解密文本时出错了。事实上,我得到了一把不是我期望的钥匙。然而,我试图找到距离最小的钥匙: def get_key(chunks, key_length):
THE MONEY IS BENEATH THE FLOOR BOARDS
ENIGMAENIGMAENIGMAENIGMAENIGMAENIGMAE
但它总是返回空的内容(b'\x00\x00\x00\x00\x00\x00\x…。
)
我认为我在获取密钥和解密文本时出错了。事实上,我得到了一把不是我期望的钥匙。然而,我试图找到距离最小的钥匙:
def get_key(chunks, key_length):
# looping through ASCII characters and XORing them with each of these bytes
best_results = [[None, 10e4] for _ in range(key_length)]
for x in string.printable:
for i in range(len(chunks)):
result = 0
for j in range(len(chunks[i])):
result += (ord(x) ^ ord(chunks[i][j]))
if best_results[i][1] > result:
best_results[i][0] = x
best_results[i][1] = result
这是全部代码:
import string
def to_hex(s):
return hex(int(s, base=16))
# Press the green button in the gutter to run the script.
def create_chunks(encrypted, key_length):
chunks = [[] for _ in range(key_length)]
for i in range(len(encrypted)):
chunks[i % key_length].append(encrypted[i])
return chunks
def get_key(chunks, key_length):
# looping through ASCII characters and XORing them with each of these bytes
best_results = [[None, 10e4] for _ in range(key_length)]
for x in string.printable:
for i in range(len(chunks)):
result = 0
for j in range(len(chunks[i])):
result += (ord(x) ^ ord(chunks[i][j]))
if best_results[i][1] > result:
best_results[i][0] = x
best_results[i][1] = result
return (best_results)
def decrypt_text(encrypted, key):
decrypted = b''
for i in range(len(encrypted)):
xor = ord(encrypted[i]) ^ ord(key[i % len(key)][0])
decrypted += bytes(xor)
return decrypted
if __name__ == '__main__':
# read input
with open("output.txt","r") as f:
encrypted = f.read()
# THE MONEY IS BENEATH THE FLOOR BOARDS
# ENIGMAENIGMAENIGMAENIGMAENIGMAENIGMAE
encrypted = "11060c67000e0b0b10670412650c0c090800110669130504650805080213650c06061f0516"
key_length = len("ENIGMA")
# we need to create chunk of length key_length
chunks = create_chunks(encrypted, key_length)
key = get_key(chunks, key_length)
print(key)
decrypted_text = decrypt_text(encrypted, key)
print(decrypted_text)
好吧,你真的需要字母频率分析。。。