Python 如何从数组打印表？

我有4个

数组

，我想打印到如下表中：

Item Code, Item, Price, Item Stock
001, Pencil, 10, 738 

从这4个

数组依此类推：

item_code = ["Item Code", "001", "002", "003", "004", "005", "006", "007", "008", "009", "010"]

item = ["Item", "Pencil", "Pen", "Eraser", "Paper", "Notebook", "Highlighters", "Card", "Stapler", "Paperclip", "Marker"]

item_price = ["Price", "10", "5", "2", "15", "20", "23", "26", "13", "17", "21"]

item_stock = stock() # This is calculated in another subheading

如何做到这一点？
一种选择是使用熊猫：

import pandas as pd
df = pd.DataFrame([item_code[1:], item[1:], item_price[1:]], index=[item_code[0], item[0], item_price[0]]).T
print(df)


  Item Code          Item Price
0       001        Pencil    10
1       002           Pen     5
2       003        Eraser     2
3       004         Paper    15
4       005      Notebook    20
5       006  Highlighters    23
6       007          Card    26
7       008       Stapler    13
8       009     Paperclip    17
9       010        Marker    21

一种选择是使用熊猫：

import pandas as pd
df = pd.DataFrame([item_code[1:], item[1:], item_price[1:]], index=[item_code[0], item[0], item_price[0]]).T
print(df)


  Item Code          Item Price
0       001        Pencil    10
1       002           Pen     5
2       003        Eraser     2
3       004         Paper    15
4       005      Notebook    20
5       006  Highlighters    23
6       007          Card    26
7       008       Stapler    13
8       009     Paperclip    17
9       010        Marker    21

您可以使用：

z=zip（商品代码、商品、商品价格、商品库存）
对于代码、i、价格、z中的库存：
打印（代码、i、价格、库存）
您可以使用：

z=zip（商品代码、商品、商品价格、商品库存）
对于代码、i、价格、z中的库存：
打印（代码、i、价格、库存）
使用一个简单的for循环：


对于范围内的i（长度（项目代码））：
打印（物料编码[i]、物料[i]、物料价格[i]、物料库存[i]）
使用一个简单的for循环：


对于范围内的i（长度（项目代码））：
打印（物料编码[i]、物料[i]、物料价格[i]、物料库存[i]）
使用简单的for循环，您可以对库存商品执行相同的操作

item_code = ["Item Code", "001", "002", "003", "004", "005", "006", "007", "008", "009", "010"]

item = ["Item", "Pencil", "Pen", "Eraser", "Paper", "Notebook", "Highlighters", "Card", "Stapler", "Paperclip", "Marker"]

item_price = ["Price", "10", "5", "2", "15", "20", "23", "26", "13", "17", "21"]

for i in range (len(item)):
    
    print(item_code[i],item[i],item_price[i])

输出：

Item Code Item Price
001 Pencil 10
002 Pen 5
003 Eraser 2
004 Paper 15
005 Notebook 20
006 Highlighters 23
007 Card 26
008 Stapler 13
009 Paperclip 17
010 Marker 21

使用简单的for循环，您可以对库存的物品执行相同的操作

item_code = ["Item Code", "001", "002", "003", "004", "005", "006", "007", "008", "009", "010"]

item = ["Item", "Pencil", "Pen", "Eraser", "Paper", "Notebook", "Highlighters", "Card", "Stapler", "Paperclip", "Marker"]

item_price = ["Price", "10", "5", "2", "15", "20", "23", "26", "13", "17", "21"]

for i in range (len(item)):
    
    print(item_code[i],item[i],item_price[i])

输出：

Item Code Item Price
001 Pencil 10
002 Pen 5
003 Eraser 2
004 Paper 15
005 Notebook 20
006 Highlighters 23
007 Card 26
008 Stapler 13
009 Paperclip 17
010 Marker 21

使用f字符串打印的更优雅的方式

item_code = ["Item Code", "001", "002", "003", "004", "005", "006", "007", "008", "009", "010"]

item = ["Item", "Pencil", "Pen", "Eraser", "Paper", "Notebook", "Highlighters", "Card", "Stapler", "Paperclip", "Marker"]

item_price = ["Price", "10", "5", "2", "15", "20", "23", "26", "13", "17", "21"]

item_stock = ["Item Stock", "10", "5", "2", "15", "20", "23", "26", "13", "17", "21"]

for item_code, item, item_price, item_stock in zip(item_code, item, item_price, item_stock):
    print(f'{item_code},{item},{item_price},{item_stock}')

Output:
Item Code,Item,Price,Item Stock
001,Pencil,10,10
002,Pen,5,5
003,Eraser,2,2
004,Paper,15,15
005,Notebook,20,20
006,Highlighters,23,23
007,Card,26,26
008,Stapler,13,13
009,Paperclip,17,17
010,Marker,21,21

使用f字符串打印的更优雅的方式

item_code = ["Item Code", "001", "002", "003", "004", "005", "006", "007", "008", "009", "010"]

item = ["Item", "Pencil", "Pen", "Eraser", "Paper", "Notebook", "Highlighters", "Card", "Stapler", "Paperclip", "Marker"]

item_price = ["Price", "10", "5", "2", "15", "20", "23", "26", "13", "17", "21"]

item_stock = ["Item Stock", "10", "5", "2", "15", "20", "23", "26", "13", "17", "21"]

for item_code, item, item_price, item_stock in zip(item_code, item, item_price, item_stock):
    print(f'{item_code},{item},{item_price},{item_stock}')

Output:
Item Code,Item,Price,Item Stock
001,Pencil,10,10
002,Pen,5,5
003,Eraser,2,2
004,Paper,15,15
005,Notebook,20,20
006,Highlighters,23,23
007,Card,26,26
008,Stapler,13,13
009,Paperclip,17,17
010,Marker,21,21

你不应该使用他没有要求的库给出答案，这可以很容易地完成，没有它你不应该使用他没有要求的库给出答案，这可以很容易地完成，没有itor更好：
对于z中的i:print（*i）
或者更好：
对于z中的i:print（*i）