Python Kivy中控制2个时钟计划的问题
我有一个钮扣。按下它时,我想在5秒后调用一个动作一次,然后在每1秒后无限次调用第二个动作。但我只需要在第一个行动完成后才开始第二个行动 我的代码:Python Kivy中控制2个时钟计划的问题,python,kivy,Python,Kivy,我有一个钮扣。按下它时,我想在5秒后调用一个动作一次,然后在每1秒后无限次调用第二个动作。但我只需要在第一个行动完成后才开始第二个行动 我的代码: #!/usr/bin/kivy import kivy kivy.require('1.7.2') from kivy.app import App from kivy.lang import Builder from kivy.uix.screenmanager import ScreenManager, Screen from kivy.uix
#!/usr/bin/kivy
import kivy
kivy.require('1.7.2')
from kivy.app import App
from kivy.lang import Builder
from kivy.uix.screenmanager import ScreenManager, Screen
from kivy.uix.button import Button
from kivy.clock import Clock
from functools import partial
Builder.load_string('''
<MenuScreen>:
Button:
id:timer1
text: 'click me'
on_press: root.val()
''')
class MenuScreen(Screen):
def val(self):
Clock.schedule_once(self.my_callback_timer1, 5)
Clock.schedule_interval(self.my_callback_timer2, 1)
def my_callback_timer1(self, interval):
print "5 sec code executed"
def my_callback_timer2(self, interval):
print "1 sec code executed"
sm = ScreenManager()
menu = MenuScreen(name='menu')
sm.add_widget(menu)
class MainApp(App):
def build(self):
return sm
if __name__ == '__main__':
MainApp().run()
我需要的是:
5 sec code executed
(wait 5 sec)
1 sec code executed
1 sec code executed
1 sec code executed
...
安排第一次回调中的第二个时钟:
class MenuScreen(Screen):
def val(self):
Clock.schedule_once(self.my_callback_timer1, 5)
def my_callback_timer1(self, interval):
print "5 sec code executed"
Clock.schedule_interval(self.my_callback_timer2, 1)
def my_callback_timer2(self, interval):
print "1 sec code executed"
谢谢…我已经想好了…和你的回答一样…:)
class MenuScreen(Screen):
def val(self):
Clock.schedule_once(self.my_callback_timer1, 5)
def my_callback_timer1(self, interval):
print "5 sec code executed"
Clock.schedule_interval(self.my_callback_timer2, 1)
def my_callback_timer2(self, interval):
print "1 sec code executed"