在字符串python中找到句子时如何提取下一个单词

我试图找到一种有效的方法，在字符串中查找一个句子，如果找到了，然后提取后面的下一个单词，例如-

string_text = """"
 create table AWSBilling202004(identity_LineItemId VARCHAR(512), identity_TimeInterval VARCHAR(512),
 create table AWSBilling202004_tagMapping (remappedUserTag VARCHAR(512), userTag VARCHAR(512));
 insert into AWSBilling202004_tagMapping(remappedUserTag, userTag) values('userTag4', 'user:BillingTeam'
 create table AWSBilling202004_costCategoryMapping (remappedCostCategory VARCHAR(512), costCategory VARCHAR(512));
 """"

在上面的文本中，每当找到

create table

时，我都想提取后面的下一个单词。上述代码的输出应为

AWSBilling202004
AWSBilling202004_tagMapping
AWSBilling202004_costCategoryMapping

正如您在上面看到的，当发现

（

）时，将提取单词直到该点

我一直在寻找正则表达式解决方案，但发现很难让它们适用于我的用例。我非常感谢任何指导或帮助。

这对我来说很有效

import re
def get_next_words(text, pattern):
    return re.findall("%s\s+([a-zA-Z0-9_]+)"%(pattern), text)


string_text = '''
 create table AWSBilling202004(identity_LineItemId VARCHAR(512), identity_TimeInterval VARCHAR(512),
 create table AWSBilling202004_tagMapping (remappedUserTag VARCHAR(512), userTag VARCHAR(512));
 insert into AWSBilling202004_tagMapping(remappedUserTag, userTag) values('userTag4', 'user:BillingTeam'
 create table AWSBilling202004_costCategoryMapping (remappedCostCategory VARCHAR(512), costCategory VARCHAR(512));
'''


print(get_next_words(string_text, "create table"))

这对我有用

import re
def get_next_words(text, pattern):
    return re.findall("%s\s+([a-zA-Z0-9_]+)"%(pattern), text)


string_text = '''
 create table AWSBilling202004(identity_LineItemId VARCHAR(512), identity_TimeInterval VARCHAR(512),
 create table AWSBilling202004_tagMapping (remappedUserTag VARCHAR(512), userTag VARCHAR(512));
 insert into AWSBilling202004_tagMapping(remappedUserTag, userTag) values('userTag4', 'user:BillingTeam'
 create table AWSBilling202004_costCategoryMapping (remappedCostCategory VARCHAR(512), costCategory VARCHAR(512));
'''


print(get_next_words(string_text, "create table"))