Python3枚举：继承另一个枚举的枚举不'；不行？
我只是想通过参考官方Python文档，特别是8.13.13.2和8.13.13.4示例，在Python3中创建一个枚举 我的目标是有一个枚举，我可以迭代，比较，还有三个独立的属性。但我一直发现这个错误：Python3枚举：继承另一个枚举的枚举不'；不行？,python,python-3.x,enums,Python,Python 3.x,Enums,我只是想通过参考官方Python文档，特别是8.13.13.2和8.13.13.4示例，在Python3中创建一个枚举 我的目标是有一个枚举，我可以迭代，比较，还有三个独立的属性。但我一直发现这个错误： AttributeError: can't set attribute 这似乎是\uuu init\uu（）构造函数中的一个错误 代码： 我首先尝试了一个这样的课程： class Hand(Enum): FIVE_OF_KIND = (6,'FIVE_OF_KIND',[5])
AttributeError: can't set attribute
\uuu init\uuclass Hand(Enum):
FIVE_OF_KIND = (6,'FIVE_OF_KIND',[5])
FOUR_OF_KIND = (5,'FOUR_OF_KIND',[4,1])
FULL_HOUSE = (4,'FULL_HOUSE',[3,2])
THREE_OF_KIND = (3,'THREE_OF_KIND',[3,1,1])
DOUBLE_PAIR = (2,'DOUBLE_PAIR',[2,2,1])
PAIR = (1,'PAIR',[2,1,1,1])
NOTHING = (0,'NOTHING',[1,1,1,1,1])
def __init__(self, val, name, struct):
self.val = val
self.name = name
self.struct = struct
def __ge__(self, other):
if self.__class__ is other.__class__:
return self.value >= other.value
return NotImplemented
def __gt__(self, other):
if self.__class__ is other.__class__:
return self.value > other.value
return NotImplemented
def __le__(self, other):
if self.__class__ is other.__class__:
return self.value <= other.value
return NotImplemented
def __lt__(self, other):
if self.__class__ is other.__class__:
return self.value < other.value
return NotImplemented
class OrderedEnum(Enum):
def __ge__(self, other):
if self.__class__ is other.__class__:
return self.value >= other.value
return NotImplemented
def __gt__(self, other):
if self.__class__ is other.__class__:
return self.value > other.value
return NotImplemented
def __le__(self, other):
if self.__class__ is other.__class__:
return self.value <= other.value
return NotImplemented
def __lt__(self, other):
if self.__class__ is other.__class__:
return self.value < other.value
return NotImplemented
class Hand(OrderedEnum):
FIVE_OF_KIND = (6,'FIVE_OF_KIND',[5])
FOUR_OF_KIND = (5,'FOUR_OF_KIND',[4,1])
FULL_HOUSE = (4,'FULL_HOUSE',[3,2])
THREE_OF_KIND = (3,'THREE_OF_KIND',[3,1,1])
DOUBLE_PAIR = (2,'DOUBLE_PAIR',[2,2,1])
PAIR = (1,'PAIR',[2,1,1,1])
NOTHING = (0,'NOTHING',[1,1,1,1,1])
def __init__(self, val, name, struct):
self.val = val
self.name = name
self.struct = struct
from enum import Enum
class OrderedEnum(Enum):
# Same as your code.
class Hand(OrderedEnum):
FIVE_OF_KIND = (6, [5])
FOUR_OF_KIND = (5, [4,1])
FULL_HOUSE = (4, [3,2])
THREE_OF_KIND = (3, [3,1,1])
DOUBLE_PAIR = (2, [2,2,1])
PAIR = (1, [2,1,1,1])
NOTHING = (0, [1,1,1,1,1])
def __init__(self, val, struct):
# No need to set self.name. It's already handled.
self.val = val
self.struct = struct
for h in Hand:
print((h.name, h.val, h.struct))
班手（枚举）：
五个种类=（6，'五个种类'，[5]）
种类四=（5，'种类四'，[4,1]）
满屋=（4，'FULL_HOUSE'，[3,2]）
三种类型=（3，'三种类型'，[3,1,1]）
双_对=（2，'DOUBLE_对'，[2,2,1]）
PAIR=（1，'PAIR'，[2,1,1,1]）
NOTHING=（0，'NOTHING'，[1,1,1,1]）
定义初始化（self、val、name、struct）：
self.val=val
self.name=名称
self.struct=struct
定义（自身、其他）：
如果self.\uuuuuu class\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
返回self.value>=其他.value
返回未执行
定义（自身、其他）：
如果self.\uuuuuu class\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
返回self.value>other.value
返回未执行
定义（自我、其他）：
如果self.\uuuuuu class\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
返回self.value=other.value
返回未执行
定义（自身、其他）：
如果self.\uuuuuu class\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
返回self.value>other.value
返回未执行
定义（自我、其他）：
如果self.\uuuuuu class\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
return self.valueEnum
对象已经有一个名称
属性（例如，请参见），显然不允许您对其进行设置–这在您考虑枚举的行为时是有意义的。您可以通过以下方式实现您想要的：
class Hand(Enum):
FIVE_OF_KIND = (6,'FIVE_OF_KIND',[5])
FOUR_OF_KIND = (5,'FOUR_OF_KIND',[4,1])
FULL_HOUSE = (4,'FULL_HOUSE',[3,2])
THREE_OF_KIND = (3,'THREE_OF_KIND',[3,1,1])
DOUBLE_PAIR = (2,'DOUBLE_PAIR',[2,2,1])
PAIR = (1,'PAIR',[2,1,1,1])
NOTHING = (0,'NOTHING',[1,1,1,1,1])
def __init__(self, val, name, struct):
self.val = val
self.name = name
self.struct = struct
def __ge__(self, other):
if self.__class__ is other.__class__:
return self.value >= other.value
return NotImplemented
def __gt__(self, other):
if self.__class__ is other.__class__:
return self.value > other.value
return NotImplemented
def __le__(self, other):
if self.__class__ is other.__class__:
return self.value <= other.value
return NotImplemented
def __lt__(self, other):
if self.__class__ is other.__class__:
return self.value < other.value
return NotImplemented
class OrderedEnum(Enum):
def __ge__(self, other):
if self.__class__ is other.__class__:
return self.value >= other.value
return NotImplemented
def __gt__(self, other):
if self.__class__ is other.__class__:
return self.value > other.value
return NotImplemented
def __le__(self, other):
if self.__class__ is other.__class__:
return self.value <= other.value
return NotImplemented
def __lt__(self, other):
if self.__class__ is other.__class__:
return self.value < other.value
return NotImplemented
class Hand(OrderedEnum):
FIVE_OF_KIND = (6,'FIVE_OF_KIND',[5])
FOUR_OF_KIND = (5,'FOUR_OF_KIND',[4,1])
FULL_HOUSE = (4,'FULL_HOUSE',[3,2])
THREE_OF_KIND = (3,'THREE_OF_KIND',[3,1,1])
DOUBLE_PAIR = (2,'DOUBLE_PAIR',[2,2,1])
PAIR = (1,'PAIR',[2,1,1,1])
NOTHING = (0,'NOTHING',[1,1,1,1,1])
def __init__(self, val, name, struct):
self.val = val
self.name = name
self.struct = struct
from enum import Enum
class OrderedEnum(Enum):
# Same as your code.
class Hand(OrderedEnum):
FIVE_OF_KIND = (6, [5])
FOUR_OF_KIND = (5, [4,1])
FULL_HOUSE = (4, [3,2])
THREE_OF_KIND = (3, [3,1,1])
DOUBLE_PAIR = (2, [2,2,1])
PAIR = (1, [2,1,1,1])
NOTHING = (0, [1,1,1,1,1])
def __init__(self, val, struct):
# No need to set self.name. It's already handled.
self.val = val
self.struct = struct
for h in Hand:
print((h.name, h.val, h.struct))