Python 我的简单假设有什么问题吗。。。埃利夫。。。陈述

此脚本接受输入的内容并将其格式化为

“1/1”

类型格式

它与前两个

elif

语句一起工作，但是当移到第三个语句时，它仍然分配数字前面的

2/

。它应该跳转到

3/

和

4/

，如下所示

非常感谢你的帮助

import re

port = input("Enter port number:")

if bool(re.search('\/', port)) == True:
    p = port

elif int(port) <= 48:
    port = "1/" + str(port)

elif int(port) >= 53 <= 100:
    port = "2/" + str(port)

elif int(port) >= 105 <= 152:
    port = "3/" + str(port)

elif int(port) >= 157 <= 204:
    port = "4/" + str(port)

print(port)

重新导入
端口=输入（“输入端口号：”）
如果布尔（重新搜索（'\/'，端口））==True：
p=端口
elif int（port）=53=105=157问题在于您试图链接比较：

elif int(port) >= 53 <= 100:

这仅适用于
int（端口）
介于53和100（含）之间的情况。您需要对其余的
elif
块进行类似的更改。
您的if条件混淆了。修正：

def getPort(port):

    # https://stackoverflow.com/questions/12265451/ask-forgiveness-not-permission-explain
    # only convert to int once, if that does not work check for / else bail out
    try:
        p = int(port)
    except ValueError:
        if "/" in port: # no need for regex
            return port
        else:
            raise ValueError("Port either integer or somthing with / in it")

    if p <= 48:               # 49-52 are not covered
        port = "1/" + port

    elif  53 <= p <= 100:     # move the condition between, the way you did it theyre True
        port = "2/" + port    # no matter because 53 <= 100 all the time

    elif 105 <= p <= 152:     # 101-104 are not covered
        port = "3/" + port

    elif 157 <= p <= 204:     # 152-156 are not covered
        port = "4/" + str(port)

    else:
        raise ValueError("Port either integer or somthing with / in it")

    return port

for p in ["1","54","99","121","180","47/11","2000"]:
    try:
        print(getPort(p))
    except ValueError as e:
        print (e)


您缺少一些端口范围，50 f.e.不包括在内，这将导致ValueError。
您的错误如下：

elif int(port) >= 53 <= 100:

port=“1/”+str（端口）
。。。端口已经是str了…在哪里使用变量p？我看到您分配了它（当re.search生成一个True时），但从未使用它。此脚本只是稍后将使用的脚本的一小部分。这就是为什么你会看到p变量。我无法继续前进，直到我先弄清楚这些步骤。这就成功了。太棒了@帕特里卡特纳，我不这么认为。我在回答中添加了一个到python文档的链接，该链接部分的第三段使用了
和
。对不起，我错了。
# Input: ["1","54","99","121","180","47/11","2000"]

1/1
2/54
2/99
3/121
4/180
47/11
Port either integer or somthing with / in it

elif int(port) >= 53 <= 100:

elif int(port) >= 53 and 53 <= 100:

port = input("Enter port number:")
int_port = int(port)    # so we don't repeat the same operation multiple unnecessary times

if bool(re.search('\/', port)):
    pass
elif int_port <= 48:
    port = "1/" + port
elif 53 <= int_port <= 100:
    port = "2/" + port
elif 105 <= int_port <= 152:
    port = "3/" + port
elif 157 <= int_port <= 204:
    port = "4/" + port

print(port)