Python 将多维列表分配给唯一值的最佳方法

将名称和值列表分配给唯一名称列表的最佳方法是什么？或者有没有一种方法可以从一开始就忽略唯一值的列表

例如：

list01 = ['John Doe', 'Jane Doe']
list02 = [['John Doe', 'John Doe', 'Jane Doe', 'John Doe', 'Jane Doe'], [10, 20, 30, 40, 50]]

最终结果应如下所示：

list03 = [['John Doe', 'Jane Doe'], [70, 80]]

list01 = ['John Doe', 'Jane Doe']
list02 = [['John Doe', 'John Doe', 'Jane Doe', 'John Doe', 'Jane Doe'], [10, 20, 30, 40, 50]]

totals = {name: 0 for name in list01}
for i in range(len(list02[0])):
    totals[list02[0][i]] += list02[1][i]

list03 = [list(totals.keys()), list(totals.values())]

list01 = ['John Doe', 'Jane Doe']
list02 = [['John Doe', 'John Doe', 'Jane Doe', 'John Doe', 'Jane Doe'], [10, 20, 30, 40, 50]]

list03 = [list01[:], [sum([x[1] for x in zip(list02[0], list02[1]) if x[0]==y]) for y in list01]]

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谢谢你的帮助，祝大家周日愉快

我知道您想要对每个名称的值求和，您可以尝试以下方法：

list03 = [['John Doe', 'Jane Doe'], [70, 80]]

list01 = ['John Doe', 'Jane Doe']
list02 = [['John Doe', 'John Doe', 'Jane Doe', 'John Doe', 'Jane Doe'], [10, 20, 30, 40, 50]]

totals = {name: 0 for name in list01}
for i in range(len(list02[0])):
    totals[list02[0][i]] += list02[1][i]

list03 = [list(totals.keys()), list(totals.values())]

list01 = ['John Doe', 'Jane Doe']
list02 = [['John Doe', 'John Doe', 'Jane Doe', 'John Doe', 'Jane Doe'], [10, 20, 30, 40, 50]]

list03 = [list01[:], [sum([x[1] for x in zip(list02[0], list02[1]) if x[0]==y]) for y in list01]]

或者，您可以尝试使用python的列表理解，可能类似于：

list03 = [['John Doe', 'Jane Doe'], [70, 80]]

list01 = ['John Doe', 'Jane Doe']
list02 = [['John Doe', 'John Doe', 'Jane Doe', 'John Doe', 'Jane Doe'], [10, 20, 30, 40, 50]]

totals = {name: 0 for name in list01}
for i in range(len(list02[0])):
    totals[list02[0][i]] += list02[1][i]

list03 = [list(totals.keys()), list(totals.values())]

list01 = ['John Doe', 'Jane Doe']
list02 = [['John Doe', 'John Doe', 'Jane Doe', 'John Doe', 'Jane Doe'], [10, 20, 30, 40, 50]]

list03 = [list01[:], [sum([x[1] for x in zip(list02[0], list02[1]) if x[0]==y]) for y in list01]]

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你的问题不清楚，请详细说明。[70,80]是从哪里来的[70,80]是从哪里来的[70,80]是从哪里来的？当你尝试这样做时，问题是什么？很抱歉，问题不清楚。我在两个列表中循环，并将分配给“list02”中名称的值相加。分配给list02中名称的值之和为150，而不是[70,80]。您为什么期望[70,80]的预期产出。非常感谢！那正是我要找的！