Python 烧瓶：一页，3个功能-只能获得1个功能打印到网页

我有一个有三个功能的程序。每个函数从不同的网页中提取数据，保存到列表中，然后打印列表

我在终端运行了这个，它运行正常

我想把这些列表打印到一个网页上

我可以打印一个函数，但我不知道如何将多个函数放入烧瓶中

以下是有效的方法：

.py文件

这是我在.html文件中打印的方式

---

我将在我的.html页面中的两个新列表中打印这些函数的数据。这里有一个简单的示例，一种方法是简化scraper函数，使其只返回列表，然后将参数添加到

render\u template（）

：

index.html

<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in china %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>
<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in korea %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>
<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in jobs %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>

{%for href，中文字幕%}

{%endfor%}


{%endfor%}


{%endfor%}

谢谢。我是根据你的建议做的。返回值，然后将函数放入变量中，并在render_模板中调用它们。干杯

<ul class="list-group col-md-4" style="padding-left: 18px;">
{% for href, caption in china %}
  <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
{% endfor %}
</ul>

def koreaJobs():
    sauce = urllib.request.urlopen('http://www.eslcafe.com/jobs/korea/').read()
    soup = bs.BeautifulSoup(sauce, 'html.parser')
    dl = soup.dl
    koreaAds = []
    korea []

    for words in dl.find_all('a'):
        links = words.get('href')
        link_text = words.text

        if ('university' in link_text.lower()) or ('universities' in link_text.lower()) or ('college' in link_text.lower()) or ('colleges' in link_text.lower()):
            koreaAds.append([links, link_text])

    for ad in koreaAds:
        korea.append(tuple(ad))
    return render_template("eslJobs.html", korea=korea)

def intlJobs():
    sauce = urllib.request.urlopen('http://www.eslcafe.com/joblist/').read()
    soup = bs.BeautifulSoup(sauce, 'html.parser')
    dl = soup.dl
    intlAds = []
    intl = []

    for words in dl.find_all('a'):
        links = words.get('href')
        link_text = words.text

        if ('university' in link_text.lower()) or ('universities' in link_text.lower()) or ('college' in link_text.lower()) or ('colleges' in link_text.lower()):
            intlAds.append([links, link_text])

    for ad in intlAds:
        intl.append(tuple(ad))
    return render_template("eslJobs.html", intl=intl)

from flask import Flask, render_template
import bs4 as bs
import urllib.request

app = Flask(__name__)

def get_ads(url):
    """ This function returns a list of tuples. """
    terms = ['universit', 'college']
    sauce = urllib.request.urlopen(url).read()  #
    soup = bs.BeautifulSoup(sauce, 'html.parser')
    ads = []
    for words in soup.dl.find_all('a'):
        links = words.get('href')
        link_text = words.text
        if any(x in link_text.lower() for x in terms):
            ads.append(tuple([links, link_text]))
    return ads

# call functions here when the app starts
china = get_ads('http://www.example.com/jobs/china/')
korea = get_ads('http://www.example.com/jobs/korea/')
jobs = get_ads('http://www.example.com/joblist/')

@app.route('/')
def index():
    # or call functions here each time a page is requested

    return render_template("index.html", china=china, korea=korea, jobs=jobs)

if __name__ == '__main__':
    app.run(debug=True)

<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in china %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>
<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in korea %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>
<ul class="list-group col-md-4" style="padding-left: 18px;">
    {% for href, caption in jobs %}
      <li class="list-group-item"><a href="{{ href }}">{{ caption }}</a></li>
    {% endfor %}
</ul>