Python 从单个列表打印

编辑：

及

是否有一个代码可以用来生成这样的结果，即打印时的输出如下所示

['Station 1 average is greater than 1.62644628099', 'Station 2 average is greater than 1.62644628099', 'Station 3 average is greater than 1.62644628099']

及

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感谢您的阅读和任何建议/帮助。

使用换行符加入列表成员

Station 1 average is greater than 1.62644628099
Station 2 average is greater than 1.62644628099
Station 3 average is greater than 1.62644628099

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用换行符连接列表成员

Station 1 average is greater than 1.62644628099
Station 2 average is greater than 1.62644628099
Station 3 average is greater than 1.62644628099

使用函数，它将打印列表中的每个元素，其中str介于两者之间。在这里，我在每个元素之间插入新行

print "\n".join(t)
print
print "\n".join(s)

第二个列表也一样：

>>> lst1 = ['Station 5 average is less than 1.62644628099', 'Station 6 average is less than 1.62644628099', 'Station 7 average is less than 1.62644628099', 'Station 8 average is less than 1.62644628099', 'Station 9 average is less than 1.62644628099', 'Station 10 average is less than 1.62644628099']
>>> print '\n'.join(lst1)
Station 5 average is less than 1.62644628099
Station 6 average is less than 1.62644628099
Station 7 average is less than 1.62644628099
Station 8 average is less than 1.62644628099
Station 9 average is less than 1.62644628099
Station 10 average is less than 1.62644628099

或者，您可以使用for循环：

>>> lst2 = ['Station 1 average is greater than 1.62644628099', 'Station 2 average is greater than 1.62644628099', 'Station 3 average is greater than 1.62644628099']
>>> print '\n'.join(lst2)
Station 1 average is greater than 1.62644628099
Station 2 average is greater than 1.62644628099
Station 3 average is greater than 1.62644628099

可能最好使用join函数，因为它实际上返回结果，因此如果您愿意，可以在以后的代码中使用它。

使用该函数，该函数将打印列表中的每个元素，其中str介于两者之间。在这里，我在每个元素之间插入新行

print "\n".join(t)
print
print "\n".join(s)

第二个列表也一样：

>>> lst1 = ['Station 5 average is less than 1.62644628099', 'Station 6 average is less than 1.62644628099', 'Station 7 average is less than 1.62644628099', 'Station 8 average is less than 1.62644628099', 'Station 9 average is less than 1.62644628099', 'Station 10 average is less than 1.62644628099']
>>> print '\n'.join(lst1)
Station 5 average is less than 1.62644628099
Station 6 average is less than 1.62644628099
Station 7 average is less than 1.62644628099
Station 8 average is less than 1.62644628099
Station 9 average is less than 1.62644628099
Station 10 average is less than 1.62644628099

或者，您可以使用for循环：

>>> lst2 = ['Station 1 average is greater than 1.62644628099', 'Station 2 average is greater than 1.62644628099', 'Station 3 average is greater than 1.62644628099']
>>> print '\n'.join(lst2)
Station 1 average is greater than 1.62644628099
Station 2 average is greater than 1.62644628099
Station 3 average is greater than 1.62644628099

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可能最好使用join函数，因为它实际上会返回结果，因此您可以在以后的代码中使用它（如果您愿意）。

不要忘记：不要忘记：+1，但是for循环更可取，因为您不必同时将整个输出的副本加载到内存中once@jamylak，列表已在内存中。此外，str.join接受任何iterable，因此可以与生成器表达式一起愉快地工作。@Johnsyweb因此您不必养成再次复制它或不必要地复制任何其他数据的习惯structures@Johnsyweb还有，str.join从list1Oh创建一个新字符串！我懂了！很抱歉，我完全误解了您的评论。+1但是for循环更可取，因为您不必同时将整个输出的副本加载到内存中once@jamylak，列表已在内存中。此外，str.join接受任何iterable，因此可以与生成器表达式一起愉快地工作。@Johnsyweb因此您不必养成再次复制它或不必要地复制任何其他数据的习惯structures@Johnsyweb还有，str.join从list1Oh创建一个新字符串！我懂了！抱歉，我完全误解了你的评论。