Python 从数据帧中查找频率并在数组中存储值

我试图编写一个python代码，以获得零值之间连续出现非零值的次数。要计算频率并存储一次出现的非零数字，数组中的零和零之间非常简单。但当我试图为连续出现超过6次的非零代码编写代码时，问题就出现了，即代码开始变得太长。 这是我试过的

rain_15Min = np.array([0,15,15,15,4,0,5,5,5,90,0,30,4,3,30,32,0,0,45,45,45,4,50,0,3,4,5,0,0,0,6,7,5,5])
R_75min=[]
# for 75 Minutes duration    
for i in range(len(rain_15Min)-5): 
    if rain_15Min[i]!= 0 and rain_15Min[i-1]== 0 and rain_15Min[i+1] !=0 and rain_15Min[i+2] !=0 and rain_15Min[i+3] !=0 and rain_15Min[i+4] !=0 and rain_15Min[i+5] == 0:
        R_75min.append(rain_15Min[i:i+5])
print("The frequency of 60min rainfall is: ")
print(len(R_75min))
print(R_75min)

---

你可以用发电机

def chunker(items):
    chunk = []
    for item in items:
        if item != 0:
            chunk.append(item)
        else:
            if chunk:
                yield chunk
                chunk = []
    if chunk:
        yield chunk

            
rain_15Min = [0,15,15,15,4,0,5,5,5,90,0,30,4,3,30,32,0,0,45,45,45,4,50,0,3,4,5,0,0,0,6,7,5,5]

chunks = [chunk for chunk in chunker(rain_15Min)]
chunk_lens = [len(chunk) for chunk in chunks]

你读过吗？

np。其中（rain_15Min[：]==0）

会给你0分，然后你可以从那里推理