Python 如何在XPath选择中包含属性

我正在使用selenium浏览页面

以下是页面来源：

<td colspan="10" align="right">
                <input type="button" name="previous" value="Previous" onclick="this.form.action = 'coca-cola-north-america-group-company-37452.htm?previous=true&currentPage=6';this.form.submit();" > 
                <input type="hidden" name="currentPage" id="currentPage" value="6" />

                <input type="button" name="next" value="Next" onclick="this.form.action = 'coca-cola-north-america-group-company-37452.htm?next=true&currentPage=6';this.form.submit();" >
            </td>


<td colspan="10" align="right">
                <input type="button" name="previous" value="Previous" onclick="this.form.action = 'coca-cola-north-america-group-company-37452.htm?previous=true&currentPage=7';this.form.submit();" > 
                <input type="hidden" name="currentPage" id="currentPage" value="7" />

现在，当我进入最后一页（下面是源代码）时，我得到了相同的xpath（用于下一页链接）---在末尾禁用了属性

。我想在这里停下来

但是，我不确定如何在xpath中包含

disabled

属性

                <input type="button" name="next" value="Next" onclick="this.form.action = 'coca-cola-north-america-group-company-37452.htm?next=true&currentPage=7';this.form.submit();" disabled>
            </td>

试试：

                <input type="button" name="next" value="Next" onclick="this.form.action = 'coca-cola-north-america-group-company-37452.htm?next=true&currentPage=7';this.form.submit();" disabled>
            </td>

//*[@name="next"][not(@disabled)]