假设python中有两个列表，一个是名字列表，一个是姓氏列表

我期望的输出是

firstName = ['abcd','efghi','jkl','mnopqr']
lastName  = ['xyz','pqrst','uvw','klmn']

我尝试过各种方法，但都失败了。我能想到的最接近的方法是

abcd xyz a.xyz@example.com
efghi pqrst e.pqrst@example.com 
jkl uvw j.uvw@example.com 
mnopqr klmn m.klmn@example.com 

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我应该怎么做？

使用基本字符串格式并按如下所示打印输出：

for x,y in zip(firstName,lastName):
    print(x,y)

输出

for i,j in zip(firstName,lastName):
    print (i+" "+j+" "+i[0]+"."+j+"@example.com")

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这将打印您要查找的输出。你真的只是想把它打印出来吗

abcd xyz a.xyz@example.com
efghi pqrst e.pqrst@example.com
jkl uvw j.uvw@example.com
mnopqr klmn m.klmn@example.com

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你想把它输出到一个文件中还是只打印到屏幕上？电子邮件地址从哪里来？@thefourthey它们显然是由名称构成的，在屏幕和文件中，我是生成邮件的人

firstName = ['abcd','efghi','jkl','mnopqr']
lastName  = ['xyz','pqrst','uvw','klmn']

for index in range(0, len(firstName)):

    first = firstName[index]
    last = lastName[index]
    email = first[0] + '.' + last + '@example.com'

    print first, last, email

for i,j in zip(firstName,lastName):
    print (i+" "+j+" "+i[0]+"."+j+"@example.com")

abcd xyz a.xyz@example.com
efghi pqrst e.pqrst@example.com
jkl uvw j.uvw@example.com
mnopqr klmn m.klmn@example.com

for x,y in zip(firstName,lastName):
    print (x,y, x[0] + r'.' + y + r'@example.com')