Python Selenium错误：在缓存中找不到元素-可能页面在查找后已更改

我正在提取url每页上的第一个“名称”字段：

for循环运行一次并引发错误：

File "srl.py", line 40, in <module>
    print state.text
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webelement.py", line 66, in text
    return self._execute(Command.GET_ELEMENT_TEXT)['value']
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webelement.py", line 404, in _execute
    return self._parent.execute(command, params)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 195, in execute
    self.error_handler.check_response(response)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/errorhandler.py", line 170, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.StaleElementReferenceException: Message: Element not found in the cache - perhaps the page has changed since it was looked up
Stacktrace:
    at fxdriver.cache.getElementAt (resource://fxdriver/modules/web-element-cache.js:8981)
    at Utils.getElementAt (file:///tmp/tmpPEHToH/extensions/fxdriver@googlecode.com/components/command-processor.js:8574)
    at WebElement.getElementText (file:///tmp/tmpPEHToH/extensions/fxdriver@googlecode.com/components/command-processor.js:11722)
    at DelayedCommand.prototype.executeInternal_/h (file:///tmp/tmpPEHToH/extensions/fxdriver@googlecode.com/components/command-processor.js:12282)
    at fxdriver.Timer.prototype.setTimeout/<.notify (file:///tmp/tmpPEHToH/extensions/fxdriver@googlecode.com/components/command-processor.js:603)

---

在运行此脚本时，只运行一次的for循环不会打印最后一个“state.text”，即使我没有做任何更改。

考虑到异常的文本，会发生以下情况：每次按下Go按钮，页面都会刷新自己加载新数据，不是通过AJAX，而是通过实际刷新-这很重要，因此，Selenium会检测页面状态的变化，并在您尝试从以前的状态访问元素时引发异常。我建议使用以下算法来解决您的问题：

current_position = 1

while True:
    try:
        state_elem = driver.find_element_by_id("state")
        all_states = state_elem.find_elements_by_tag_name("option")
        state = all_states[current_position]
        print "start ",
        print state.text

        print "state value is %s" % state.get_attribute("value")
        state.click()
        driver.implicitly_wait(2)

        driver.find_element_by_name("go").click()

        name = driver.find_element_by_xpath("//div[span='Name'][1]/span/following-sibling::span[2]")
        print name.text
        print "end ",
        print state.text
        current_position += 1
    except:
        break

---

这样，每次在新生成的页面上选择下一个选项时，都不会出现以前出现的异常。

要显示什么？下拉列表中的状态名称..或任何其他？是的状态名称以及我使用xpath提取的第一个“名称”字段@Sarithag尝试使用此xpath获取名字：.//*[@id='qname']。我很容易获取名字。。。那没问题。。我没有得到的是，我的代码没有打印下一个州，即“Assam”@SarithaG，它打印了以下内容：国家价值是印度开始安得拉邦国家价值是安得拉邦AMBICARE诊所和诊断结束回溯最近的电话最后：我投票，因为我原则上相信这是正确的。但是，您是否认为中断属于try：而不是except:？

current_position = 1

while True:
    try:
        state_elem = driver.find_element_by_id("state")
        all_states = state_elem.find_elements_by_tag_name("option")
        state = all_states[current_position]
        print "start ",
        print state.text

        print "state value is %s" % state.get_attribute("value")
        state.click()
        driver.implicitly_wait(2)

        driver.find_element_by_name("go").click()

        name = driver.find_element_by_xpath("//div[span='Name'][1]/span/following-sibling::span[2]")
        print name.text
        print "end ",
        print state.text
        current_position += 1
    except:
        break