Python 模板的对象的有序列表
试着点我的queryset。我知道有Python 模板的对象的有序列表,python,django,orm,Python,Django,Orm,试着点我的queryset。我知道有order\u by()但排序是由POST数据定义的,而不是数据库中的任何内容 sort----lookup-----display objects (darn, orderless) 1. Joe \ 2. Fred => {Fred, Joe, Marty} 3. Marty / 这是我到目前为止的视图代码 from operator import itemgetter #... # Sorted Tuple
order\u by()
但排序是由POST数据定义的,而不是数据库中的任何内容
sort----lookup-----display objects (darn, orderless)
1. Joe \
2. Fred => {Fred, Joe, Marty}
3. Marty /
这是我到目前为止的视图代码
from operator import itemgetter
#...
# Sorted Tuples! Now what?? (this is not used)
i1 = sorted([(k,v) for k,v in request.POST.items() if k[:2] == 'i_'], key=itemgetter(1))
e1 = sorted([(k,v) for k,v in request.POST.items() if k[:2] == 'e_'], key=itemgetter(1))
# Unsorted lists to use in ORM :/
i = [int(v) for k,v in request.POST.items() if k[:2] == 'i_']
e = [int(v) for k,v in request.POST.items() if k[:2] == 'e_']
# It's an orderless QuerySet...
i_students = Student.objects.filter(pk__in=i)
e_students = Student.objects.filter(pk__in=e)
如果你有任何想法,让我知道:)我想在模板中这样做
<ol>
{% for s in i_students %}
<li>{{ s }}</li>
{% endfor %}
</ol>
这回答了我的问题: 我从帖子里得到了这样的东西:
i_0 -> 3
i_1 -> 26
i_2 -> 12
我返回排序后的对象,如下所示:
i_tuples = sorted([(k,v) for k,v in request.POST.items() if k[:2] == 'i_'], key=itemgetter(0))
i_pk_list = [v for (k,v) in i_tuples]
clauses = ' '.join(['WHEN id=%s THEN %s' % (pk, i) for i, pk in enumerate(i_pk_list)])
ordering = 'CASE %s END' % clauses
i_students = Student.objects.filter(pk__in=i_pk_list).extra(
select={'ordering': ordering}, order_by=('ordering',))
这是相当混乱的,所以如果有人有更好的解决方案排序查询集,让我知道
i_tuples = sorted([(k,v) for k,v in request.POST.items() if k[:2] == 'i_'], key=itemgetter(0))
i_pk_list = [v for (k,v) in i_tuples]
clauses = ' '.join(['WHEN id=%s THEN %s' % (pk, i) for i, pk in enumerate(i_pk_list)])
ordering = 'CASE %s END' % clauses
i_students = Student.objects.filter(pk__in=i_pk_list).extra(
select={'ordering': ordering}, order_by=('ordering',))