Python 使用海龟&x27；s在循环中单击一次

我试图从函数中字符串的

dict

创建一个简单的接口。每个字符串用于显示文本和一个可单击的海龟（使用

onclick（）

使海龟可单击）。这样我就可以点击海龟，输入一些值

但是，如果我理解正确的话，当函数通过字典运行完循环后，循环应该定义的所有变量都被重新定义为通过循环的最后一个变量，字典的最后一个元素。因此，

onclick（）

函数只返回字典的最后一个元素

有没有办法让一个

onclick（）

函数对字典中的每个元素做出不同的反应/对应？我真的不想为字典的每个元素编写一堆

onclick（）

函数。我想学一种更好的方法

list_alunos={'joao': ['5', 'm'],'maria': ['5', 'm'],'lobo': ['5', 'm'],'mau': ['5', 'm']}
def caca(dictx,file):
    import turtle
    mes=file
    vert=350
    hor=-600


    def got(t,x,y,d) :
        t.penup()
        t.goto(x,y)
        t.pendown()
        t.seth(d)

    def text(t,text, size, color, pos1, pos2):
        t.penup()
        t.goto(pos1, pos2)
        t.color(color)
        t.begin_fill()
        t.write(text, font=('Arial', size, 'normal'))
        t.end_fill()




    new_vert = vert
    for key in dictx:
        nome = key
        if vert == -340:
            new_vert = 350
            new_hor = hor + 250
        if vert!= -340:
            new_vert= new_vert-30
            new_hor = hor
            txt_vert = new_vert - 15
            txt_hor = new_hor + 20

        screen = turtle.Screen()

        width = 1200
        height = 1500
        turtle.screensize(width, height)



        tnome = turtle.Turtle(shape='turtle')
        tnome.color('pink')
        textnome = turtle
        tnome.speed('fastest')
        textnome.speed('fastest')

        text(textnome, '%s' %(nome), '20', 'pink', txt_hor,txt_vert)

        got(tnome,new_hor,new_vert,0)
        def tnome_handler(x, y):

            pos = list(dictx.keys()).index(nome)
            listt = list(dictx)

            pnt = screen.textinput(' pontuação', '%s:  '%(listt[pos]))
            pnt = [int(x) for x in pnt.split()]
            if len(pnt) == 5 :
                with open('%s.py' %(mes), 'a') as fd:
                    fd.write('\n%s.pontuacao(%i,%i,%i,%i,%i)' % (nome,pnt[0],pnt[1],pnt[2],pnt[3],pnt[4]))
                tnome.color('blue')
        tnome.onclick(tnome_handler)


caca(list_alunos,'mm')

---

我相信下面对您的代码进行的修改会满足您的需求。它有效地为每个唯一响应它的海龟/按钮生成一个自定义处理程序：

from turtle import Screen, Turtle

WIDTH, HEIGHT = 1200, 1500

dict_alunos = {'joao': ['5', 'm'], 'maria': ['5', 'm'], 'lobo': ['5', 'm'], 'mau': ['5', 'm']}

def text(t, text, size, color, x, y):
    t.penup()
    t.goto(x + size, y - size/2)
    t.color(color)
    t.write(text, align='left', font=('Arial', str(size), 'normal'))
    t.goto(x, y)

def caca(dictionary, mes):

    def tnome_handler(nome, turtle, x, y):

        pnt = screen.textinput('pontuação', '%s:  ' % (nome))
        pnt = [int(x) for x in pnt.split()]

        if len(pnt) == 5:
            with open('%s.py' % (mes), 'a') as fd:
                fd.write('s.pontuacao(%i, %i, %i, %i, %i)\n' % (nome, pnt[0], pnt[1], pnt[2], pnt[3], pnt[4]))

        turtle.color('blue')

    vert = 350
    hor = -600

    new_vert = vert

    for nome in dictionary:

        if vert == -340:
            new_vert = 350
            new_hor = hor + 250

        if vert != -340:
            new_vert = new_vert - 30
            new_hor = hor
            txt_vert = new_vert - 15
            txt_hor = new_hor + 20

        turtle = Turtle(shape='turtle')
        turtle.color('pink')
        turtle.speed('fastest')
        turtle.setheading(0)

        text(turtle, '%s' % (nome), 20, 'pink', txt_hor, txt_vert)

        turtle.onclick(lambda x, y, n=nome, t=turtle: tnome_handler(n, t, x, y))

screen = Screen()
screen.setup(WIDTH, HEIGHT)

caca(dict_alunos, 'mm')

screen.mainloop()

我还修改了代码以适应更常见的编程设计