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使用字典清理域名的Python正则表达式替换_Python_Regex - Fatal编程技术网

使用字典清理域名的Python正则表达式替换

使用字典清理域名的Python正则表达式替换,python,regex,Python,Regex,对于输出,需要将括号中包含的数字替换为句点“.”。同时移除域开头和结尾的括号 我们可以用这个吗?如果可以,怎么用 代码 import re log = ["4/19/2020 11:59:09 PM 2604 PACKET 0000014DE1921330 UDP Rcv 192.168.1.28 f975 Q [0001 D NOERROR] A (7)pagead2(17)googlesyndication(3)com(0)", "4/19/202

对于输出,需要将括号中包含的数字替换为句点“.”。同时移除域开头和结尾的括号

我们可以用这个吗?如果可以,怎么用

代码

import re

log = ["4/19/2020 11:59:09 PM 2604 PACKET  0000014DE1921330 UDP Rcv 192.168.1.28   f975   Q [0001   D   NOERROR] A      (7)pagead2(17)googlesyndication(3)com(0)",
       "4/19/2020 11:59:09 PM 0574 PACKET  0000014DE18C4720 UDP R cv 192.168.2.54    9c63   Q [0001   D   NOERROR] A      (2)pg(3)cdn(5)viber(3)com(0)"]

rx_dict = { 'query': re.compile(r'(?P<query>[\S]*)$') }

for item in log:
    for key, r_exp in rx_dict.items():
        print(f"{r_exp.search(item).group(1)}")
首选输出

(7)pagead2(17)googlesyndication(3)com(0)
(2)pg(3)cdn(5)viber(3)com(0)
pagead2.googlesyndication.com
pg.cdn.viber.com

实用python用法:

log = ["4/19/2020 11:59:09 PM 2604 PACKET  0000014DE1921330 UDP Rcv 192.168.1.28   f975   Q [0001   D   NOERROR] A      (7)pagead2(17)googlesyndication(3)com(0)",
       "4/19/2020 11:59:09 PM 0574 PACKET  0000014DE18C4720 UDP R cv 192.168.2.54    9c63   Q [0001   D   NOERROR] A      (2)pg(3)cdn(5)viber(3)com(0)"]

import re

urls = [re.sub(r'\(\d+\)','.',t.split()[-1]).strip('.') for t in log]

print (urls)
输出:

['pagead2.googlesyndication.com', 'pg.cdn.viber.com']
['pagead2.googlesyndication.com', 'pg.cdn.viber.com']

通过规则优化字典:

log = ["4/19/2020 11:59:09 PM 2604 PACKET  0000014DE1921330 UDP Rcv 192.168.1.28   f975   Q [0001   D   NOERROR] A      (7)pagead2(17)googlesyndication(3)com(0)",
       "4/19/2020 11:59:09 PM 0574 PACKET  0000014DE18C4720 UDP R cv 192.168.2.54    9c63   Q [0001   D   NOERROR] A      (2)pg(3)cdn(5)viber(3)com(0)"]

import re

urls = [re.sub(r'\(\d+\)','.',t.split()[-1]).strip('.') for t in log]

print (urls)
如果要通过字典应用连续规则,请一直转到
lambda

import re 

rules = {"r0": lambda x: x.split()[-1],
         "r1": lambda x: re.sub(r'\(\d+\)','.',x),
         "r2": lambda x: x.strip(".")}

result = []
for value in log:  
    result.append(value)
    for r in rules:
        result[-1] = rules[r](result[-1])

print(result)
输出:

['pagead2.googlesyndication.com', 'pg.cdn.viber.com']
['pagead2.googlesyndication.com', 'pg.cdn.viber.com']

是的,您可以使用
re.sub
。我假设你有这本字典,所以你可以从日志中提取多个片段。您可以这样做:


打字错误<代码>r“\(\d+\)”?结果中仍然有太多的“
”。
,并且您有一些(或)不匹配。谢谢,但是如何在我上面提供的代码中实现?@pab我怀疑您能做到。您可以使用我在Dictionary Refineration via rules中详述的链式解决方案,它与您的类似。我想不出任何一步正则表达式可以解决您的需求。